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lesya692 [45]
2 years ago
6

The cost of 1 dozen pencil is Rs.96.what is the cost of 2 pencils​

Mathematics
2 answers:
guajiro [1.7K]2 years ago
5 0

Answer:

1 dozen pencil =12pencil

given,cost of 1 dozen pencil=Rs.96

cost of 1 pencil =Rs.96/12=8 [1 dozen pencil =12pencil ]

cost of 2 pencil = Rs.(8×2)=Rs.16

natali 33 [55]2 years ago
3 0

Answer:

Rs.16

Step-by-step explanation:

Divide the cost of Rs.96 by 12 then multiply by 2

cost of 1 pencil = Rs.96 ÷ 12 = Rs.8

cost of 2 pencils = 2 × Rs.8 = Rs.16

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Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e
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Answer:

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Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in R^{2}. To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.  

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle

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\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

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