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Kruka [31]
3 years ago
14

Whats the definition of right triangle​

Mathematics
2 answers:
OlgaM077 [116]3 years ago
5 0

Answer:

a triangle with a right angle

Step-by-step explanation:

LuckyWell [14K]3 years ago
5 0

Answer: A triangle in which one of the interior angles is 90° is called a right triangle. The longest side of the right triangle, which is also the side opposite the right angle, is the hypotenuse and the two arms of the right angle are the height and the base.

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Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Svetllana [295]

The equation x^{2} -4=0~~and~~4x^2=16 are true for  x = -2 and x = 2.

The given equations are given as:

x^2-4=0\\\\x^2=-4\\\\3x^2+12=0\\\\4x^2=16\\\\2(x-2)^2=0

We need to select two equations that are true for x = -2 and x = 2.

<h3>What are the solutions to an equation ?</h3>

The solutions of an equation are the values that satisfy the given equation or make the equation true when substituted for unknowns in the equations.

Example:

x - 2 = 2

Here the solution for x - 2 = 2 is 4 because x = 4 will make the equation true.

4 - 2 = 2

2 = 2

Let's find the solutions for each equation.

1.

x^2 - 4=0

x^{2} = 4

x = \sqrt{4} = ± 2

x = = 2 and x = -2

2.

x^2 =-4

x = \sqrt{-4}

x = \sqrt{-1 \times 4} = \sqrt{-1}\times\sqrt{4}

x = ± 2 \sqrt{-1}

x = 2i and x = -2i         where i = \sqrt{-1}

3.

3x^{2} + 12  = 0

x^{2} = -12 / 3 = -4

x = \sqrt{-1} \sqrt{4}

x = ± 2\sqrt{-1}

x = 2i and x = -2i

4.

4x^{2} = 16

x^{2} = 16 / 4

x^{2} = 4

x = \sqrt{4}

x = ±2

x = 2 and x = -2

5.

2(x-2)^2 = 0

(x-2)^2 = 0

x - 2 = 0

x = 2.

Thus the equation x^{2} -4=0~~and~~4x^2=16 have solutions x = -2 and x = 2.

Learn more about solutions of equations here:

brainly.com/question/14506845

#SPJ1

4 0
2 years ago
4% of how many days is 56 days
gulaghasi [49]
56/.04=1400

Is that what you meant?
6 0
4 years ago
BRAINLIEST WILL GIVE
Ksivusya [100]
14
bc 4^2 is 16. 16-2=14
8 0
3 years ago
What is x+y=10;y=x+10
Alenkasestr [34]

[ Answer ]

\boxed{\bold{X \ = \ 0, \ Y \ = \ 10}}

[ Explanation ]

  • System Of Equations \bold{\left \{ {X \ + \ Y \ = \ 10} \atop {Y \ + \ X \ = \ 10}} \right.}

-----------------------------------

  • [Substitute] Y = X + 10

\bold{\begin{bmatrix}x+x+10=10\end{bmatrix}}

  • Isolate x for x + x + 10 = 10: x = 0

For y = 10

Substitute x = 0

Y = 0 + 10

0 + 10 = 10

y = 10

  • Solutions

X = 0

Y = 10

\boxed{\bold{[] \ Eclipsed \ []}}

3 0
3 years ago
Write an equation for the line perpendicular to y=1/3x-2 and passing through the point (3,3)
maria [59]

line given slope = x coefficient = 1/3

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

line slope (m) = -3

line equation formula = y = mx + b

y = -3x + b

from the point given

x = 3

y= 3

3 = -9 + b

b = 12

y = -3x + 12

6 0
3 years ago
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