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zheka24 [161]
3 years ago
14

What is x+y=10;y=x+10

Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0

[ Answer ]

\boxed{\bold{X \ = \ 0, \ Y \ = \ 10}}

[ Explanation ]

  • System Of Equations \bold{\left \{ {X \ + \ Y \ = \ 10} \atop {Y \ + \ X \ = \ 10}} \right.}

-----------------------------------

  • [Substitute] Y = X + 10

\bold{\begin{bmatrix}x+x+10=10\end{bmatrix}}

  • Isolate x for x + x + 10 = 10: x = 0

For y = 10

Substitute x = 0

Y = 0 + 10

0 + 10 = 10

y = 10

  • Solutions

X = 0

Y = 10

\boxed{\bold{[] \ Eclipsed \ []}}

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Answer: The slope is -2/1

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The total cost to rent 5 chairs and 3 tables is $27. The total cost to rent 2 chairs and 12 tables is $81. What is the cost to r
kati45 [8]

The cost to rent each chair is $1.5 and cost to rent each table is $6.5

<h3>Applications of systems of linear equations </h3>

From the question, we are to determine the cost to rent each chair and each table

Let c represent chair

and

t represent table

From the given information,

The total cost to rent 5 chairs and 3 tables is $27

That is,

5c + 3t = 27 ------------ (1)

Also,

The total cost to rent 2 chairs and 12 tables is $81

That is,

2c + 12t = 81 ---------- (2)

Now, solve the equations simultaneously

5c + 3t = 27 ------------ (1)

2c + 12t = 81 ---------- (2)

Multiply equation (1) by 2 and multiply equation (2) by 5

2 × [5c + 3t = 27 ]

5 × [2c + 12t = 81 ]

10c + 6t = 54        ------------- (3)

10c + 60t = 405   ------------- (4)

Subtract equation (4) from equation (3)

10c + 6t = 54        

10c + 60t = 405

---------------------------

-54t = -351

t = -351/-54

t = 6.5

Substitute the value of t into equation (2)
2c + 12t = 81

2c + 12(6.5) = 81

2c + 78 = 81

2c = 81 - 78

2c = 3

c = 3/2

c = 1.5

∴ The cost of chair is $1.5 and cost of table is $6.5

Hence, the cost to rent each chair is $1.5 and cost to rent each table is $6.5

Learn more on Solving system of linear equations here: brainly.com/question/13729904

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Remark

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================

Now look at the second equation

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===============

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