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Katena32 [7]
3 years ago
12

The price of a calculater has decreased from $200 to $150. What is the percentage of decrease?

Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

200-150=50

50/200=0.25

have a nice day!

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Solve for 2:<br> 2x + 62°<br> 52 + 38°<br> 2 =
Paladinen [302]

Answer:

The answer is 8°

Step-by-step explanation:

2x + 62° = 5x + 38°

2x – 2x + 62° – 38° = 5x – 2x + 38° – 38°

24° = 3x

3x = 24°

3x/3 = 24°/3

x = 8°

Thus, The value of x is 8°

<u>-TheUnknownScientist 72</u>

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2 years ago
Which equation shows y-5=x converted to slope intercept form.
andreyandreev [35.5K]

Answer:

C) y = x + 5

Step-by-step explanation

Add 5 to both sides

8 0
3 years ago
Find the altitude of an equilateral triangle whose perimeter is 18
Rainbow [258]

Answer:

3√3 units

Step-by-step explanation:

We are asked to find the altitude of the equilateral triangle whose perimeter is 18 . Firstly let us find the side of the∆.

\rm \implies a + a + a = 18 \\\\\rm\implies 3a = 18  \\\\\rm\implies a = 6

Now we know that in a equilateral triangle , the altitude of the triangle with side length a is ,

\rm\implies Altitude =\dfrac{\sqrt3}{2} a

Plug in the value of a that is 6 , we will get ,

\rm\implies Altitude =\dfrac{\sqrt 3}{2} a  \\\\\rm\implies Altitude =\dfrac{ \sqrt3}{2}\times 6  \\\\\rm\implies Altitude = \sqrt3 \times 3  \\\\\rm\implies\boxed{ \bf Altitude = 3\sqrt3 \ units }

5 0
3 years ago
What is the solution to this system of linear equations?
Alex777 [14]

Answer:

(6, 2)

Step-by-step explanation:

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3 years ago
A random variable is not normally distributed, but it is mound shaped. It has a mean of 11 and a standard deviation of 4.
mariarad [96]

Using the Central Limit Theorem, nothing can be stated about the shape of the sampling distribution for the sample mean, as the sample size is less than 30.

<h3>What does the Central Limit Theorem state?</h3>

It states that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the sampling distribution is also approximately normal, as long as n is at least 30.

In this problem, we have a skewed variable and n < 30, hence nothing can be stated about the shape of the sampling distribution for the sample mean.

More can be learned about the Central Limit Theorem at brainly.com/question/16695444

#SPJ1

8 0
2 years ago
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