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Pachacha [2.7K]

3 years ago

12

A pool measures 100 meters by 100 meters. A toddler, inside the pool, throws a ball and it lands 60 centimeters from one edge of

the pool. How far is the ball from the opposite edge of the pool?

1 answer:

allsm [11]3 years ago

7 0

100 m = 10,000 cm thus 10,000 cm - 60 cm = <span>9,940 cm or 9.940 m</span>

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(-3,20) (3,0) (18,20) (13,18) is it a function

S_A_V [24]

Answer: No

Step-by-step explanation: The table does not have a function rule that is linear, quadratic, or cubic.

4 0

3 years ago

Need help with this please!! The scatter plot shows the results of a survey in which 10 students were asked how many hours they

Anna11 [10]

5 students scored a 90 or above. If you look at the axis that says “test scores” just count the number of dots on the “90” line and above

7 0

3 years ago

Read 2 more answers

A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

So

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

3 years ago

Round 8250 to the nearest hundre

Alexxx [7]

It is 8300 cause 5 is bigger than 2 so 83 and hen 00 : 83000

4 0

4 years ago

Read 2 more answers

Find one value of x for which f(2) & f(x)=4

igomit [66]

The first thing we must do for this case is to observe the value of the y coordinate for a given value of the x coordinate.
We have then:
f (x) = - 4: occurs when x = 0
On the other hand, for x = 2 we have:
f (2) = - 2
Answer:
f (x) = - 4: occurs when x = 0
f (2) = - 2

4 0

3 years ago