All categories

3 years ago

If a pack of ramen noodles cost $3.48 what is the unit rate (in cents)?

Mathematics

1 answer:

tresset_1 [31]3 years ago

3 0

Answer:

348 cents per pack

Step-by-step explanation:

$3.48 348 cents

----------- or ----------------- = 348 cents per pack

1 pack 1 pack

You might be interested in

(04.05, 04.06 MC)

Snowcat [4.5K]

Answer:

siblings. Each cupcake costs $2, and each piece of fudge costs $1.

This system of inequalities models the scenario:

2x + y = <8

x + y > 4

Part A: Describe the graph of the system of inequalities, including shading and the types of lines graphed. Provide a description of the solution set. (4 points)

Part B: Is the point (8, 10) included in the solution area for the system? Justify your answer mathematically. (3 points)

Part

5 0

3 years ago

How to find the limit of that question

jeka94

Factor the numerator using difference of cubes:
$a^3 - b^3 = (a-b)(a^2 +ab+b^2)$
a = x
b = 2

$\frac{x^3 - 8}{x-2} = \frac{(x-2)(x^2 +2x+4)}{x-2} = x^2 +2x+4$

Now you can evaluate limit as x=2.
$\lim_{x \to 2} (x^2 +2x+4) = 2^2 +2(2)+4 = 12$

5 0

4 years ago

One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.

Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 ) pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both = $ 39

I.e 2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = $\frac{39}{6}$ = $\frac{13}{2}$

∴ sw = $\frac{13}{2}$ × $\frac{3}{2}$

or, sw = $\frac{39}{4}$

Now, the ratio of the amount for swordfish to the amount of salmon = $\frac{\frac{39}{4}}{\frac{13}{2}}$

I.e The ratio = $\frac{6}{4}$

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0

3 years ago

*brainliest for best answer thank you* Solve for b.

vekshin1

Hello from MrBillDoesMath!

Answer:

The fourth choice, b = +\- sqrt( sg + a^2)

Discussion:

s = (b^2 - a^2)/g => multiply both sides by "g"

sg = b^2 - a^2 => add a^2 to both sides

sg + a^2 = b^2 => take the square root of each side

b = +\- sqrt( sg + a^2)

which is the fourth choice.

Thank you,

MrB

7 0

3 years ago

Can someone please explain how Evaluating expressions works....

siniylev [52]

When you evaluate something you find it’s value. it can also be referred to as simplifying or solving the equation. think of it as 1+2+3 once that equation has been evaluated the answer will be 6. hope this explanation makes some sense:))

3 0

3 years ago