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WITCHER [35]
3 years ago
12

Pls solve showing steps, thanks! 7^4n+19/7^3n-1•7^n+20

Mathematics
1 answer:
Vinvika [58]3 years ago
7 0

Answer:

This expression can be simplified to 1

Step-by-step explanation:

\frac{7^{4n + 19}}{7^{3n - 1}\times{7^{n + 20}}}\\\\= \frac{7^{4n + 19}}{7^{3n - 1 + n + 20}}\\\\= \frac{7^{4n + 19}}{7^{(3n + n) + (20 - 1)}}\\\\= \frac{7^{4n + 19}}{7^{4n + 19}}\\\\= 1

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Answer:

2x^2+3x is the expression which is equivalent to  x\left(2x+3\right).

In other words:

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Step-by-step explanation:

Given the expression

x\left(2x+3\right)

solving

x\left(2x+3\right)

\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac

a=x,\:b=2x,\:c=3

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=2x^2+3x            ∴  2xx=2x^2

Thus,

x\left(2x+3\right)=2x^2+3x

Therefore, 2x^2+3x is the expression which is equivalent to  x\left(2x+3\right).

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Step-by-step explanation:

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