Your method is completely correct. The first term will be 6 and each subsequent term can be obtained by adding 6 to the previous one, meaning the common difference is 6. The number of terms is given by the highest number that is divisible by 6 and dividing it by 6; that is 996/6 = 166
Then we simply apply the formula for arithmetic sequence sum:
S = n/2 [2a₁ + (n - 1)d]
S = 166/2 [ 2(6) + (166 - 1)6]
S = 83,166
Answer:
81 x y^5
Step-by-step explanation:
Simplify the following:
9×3×3 x y^4 y
3×3 = 9:
9×9 x y^4 y
9 x y^4×9 y = 9×9 x y^(4 + 1):
9×9 x y^(4 + 1)
4 + 1 = 5:
9×9 x y^5
9×9 = 81:
Answer: 81 x y^5
Step-by-step explanation:
coefficient=w
variable=w
result=
32=w-4
w=4+32
w=36
constant=32,4
Answer:
The first deal:10 tacos for $7
Step-by-step explanation:
5 times 3.20 = 16$ and 10 tacos=$7
