Answer:
Step-by-step explanation:
1)
?/10 =4/5
?/5×2 =4/5
4×2/5×2 =8/10 ... the number is : 8
2)
?/4 = 11/4....the number is : 11
Answer:
Step-by-step explanation:
- 20 + 2 < x/3 - 8
- 22 + 8 < x /3
- 30 < x /3
- 30*3 < x
- 90 < x
- x > 90
Correct choice is C
The ratio of the number of girls to the total number of children is 7 : 16.
<h3>
Ratio is defined as follows:</h3>
- It is a comparison between two or more numbers that measures sizes in relation to each other
- It describe how much of a thing is compared to another.
The number of girls in the playground = 7
The number of boys in the playground = 9
The total number in the playground is the sum of the number of girls and the number of boys.
Therefore,
total children in the playground = 7 + 9 = 16
The ratio of the number of girls to the total number of children can be express as follows:
learn more on ratio here: brainly.com/question/26169121?referrer=searchResults
As Tina only has 1/4 of a cake. For simplicity sake we can do the calculation with a whole cake and then multiply by four!
First it is stated that cake is divided into six pieces, giving us our first number.
So,
6 x 4 = 24
This means that each friend will get 1/24th of the whole cake.
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.