Answer:
A. The football does not reach a height of 15ft
Step-by-step explanation:
Given

Required
Determine which of the options is true
The option illustrates the height reached by the ball.
To solve this, we make use of maximum of a function
For a function f(x)
Such that:
:

i.e we first solve for 
Then substitute
for x in 
In our case:
First we need to solve
Then substitute
for t in 
By comparison:






Substitute
for t in 






This implies that the maximum height reached is 14.0625ft.
So, the option that answers the question is A because 
1. Square of side= 6cm
2. Rectangle of side= 9cm x 4cm
3. Circle of radius is 6
Only the first statement is true.
300 miles in 1h 40m
300 miles in 100m
300 / 100 = 3
3 miles per minute
3 x 60 = 180
180 miles per hour
I hope this helps
Answer:
150 pi inches or 471.239 inches traveled
Step-by-step explanation:
First, close your eyes, and think about the distance a bike travels after one rotation of the wheel.
You will come to the realization that a full rotation of the wheel makes you travel the circumference of the wheel
The formula for circumference is 2(pi)(r) or (pi)(diameter)
We are given diameter, so let's find distance traveled for one rotation
pi(15 inches) = 15pi inches per rotation.
There are 10 rotations, so:
(15pi inches/rotation)(10 rotations) = 150pi inches travelled
150 x pi = 471.239 inches traveled