Answer:
The plane's distance from the radar station will increase about 8 miles per minute when it is 5 miles away from it.
Step-by-step explanation:
When the plane passes over the radar station, the current distance is the altitude h = 2. Then it moves b horizontally so that the distance to the station is 5. We can form a rectangle triangle using b, h and the hypotenuse 5. Therefore, b should satisfy
h²+b² = 5², since h = 2, h² = 4, as a result
b² = 25-4 = 21, thus
b = √21.
Since it moved √21 mi, then the time passed is √21/540 = 0.008466 hours, which is 0.51 minutes. Note that in 1 minute, the plane makes 540/60 = 9 miles.
The distance between the plane and the radar station after x minutes from the moment that the plane passes over it is given by the function

We have to compute the derivate of f in x = 0.51. The derivate of f is given by

also,

The plane's distance from the station will increase about 8 miles per minute.
Answer:
3:5
Step-by-step explanation:
s:m = 2:3
m:i = 9:10
convert m to same number so they are comparable
s:m = 6:9 (multiple so the ratio is still the same as 2:3)
m:i = 9:10 (the same thing as before)
s:i = 6:10
s:i = 3:5 (simplify)
You need to first make everything positive:
x^2=36
Then you need to get the square root of each side:
x=6 or -6
Hope this helps :)
182 Let x = width then y = 6x - 91. P (perimeter) = 2x + 2y = 84 then
2(x) + 2(6x - 91) = 84 | 2x + 12x - 182 =84 | 14x = 84 + 182 | 14x = 266 | x = 19 cm
y = 6x - 91 | y = 6 (19) - 91 | y = 114 - 91 | y = 23 cm
Check: P = 2x + 2y | P = 2(19) + 2(23) | P = 38 + 46 | P = 84 cm (Checked)
He would have done 10+10+10 like for each stick then + How ever many ones there were and then we would have done the same for the other set . Soorry if I'm wrong