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2 years ago

Solve each system of equations using the substitution method

Mathematics

1 answer:

boyakko [2]2 years ago

7 0

Step-by-step explanation:

y=-3+5x

substitute y into equation 2

3x-8y=24

3x-8(-3+5x)=24

3x+24-40x=24

x=0

y=-3+5(0)

y=-3

(x,y)=(0,3)

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See pictures attached below. Will give Brainliest!

Phoenix [80]

Question 1 Answer:

Aunt 1 and Grandma 1 would fill gift bags.

Mom and Aunt 2 would make centerpieces.

You and Grandma 2 would blow up balloons.

Since you are pairing up to complete the tasks, these pairs each have the shortest times in their respective categories and therefore are the most logical pairing to complete tasks.

Question 2 Answer:

We use algebra and our previous pairings to determine the length of each task.

Gifts Bags --> 6/7 hours

x = time together

$\frac{1}{x}$ = rate of completion

Aunt 1 = $\frac{1}{1.5}$ Grandma 1 = $\frac{1}{2}$

$\frac{2}{3} +\frac{1}{2} = \frac{1}{x}$

$\frac{7}{6} = \frac{1}{x}$

$x = \frac{6}{7}$

Centerpieces --> 7/4 hours

x = time together $\frac{1}{x}$ = rate of completion

Mom = $\frac{1}{3.5}$ Aunt 2 = $\frac{1}{3.5}$

$\frac{2}{7} + \frac{2}{7} = \frac{1}{x}$

$\frac{4}{7} = \frac{1}{x}$

$x = \frac{7}{4}$

Balloons --> 15/16 hours

x = time together $\frac{1}{x}$ = rate of completion

You = $\frac{1}{1.5}$ Grandma 2 = $\frac{1}{2.5}$

$\frac{2}{3} + \frac{2}{5} = \frac{1}{x}$

$\frac{16}{15} = \frac{1}{x}$

$x = \frac{15}{16}$

Shortest amount of time to complete all tasks is:

$\frac{6}{7} + \frac{7}{4} + \frac{15}{16} = \frac{397}{112}$ ≈ 3.54 hours

Converting hours to hours and minutes --> 3 hours 32 minutes

Therefore they must arrive by 5:28pm to complete the tasks in time to leave at 9:00pm.

8 0

2 years ago

6 = a divided by 4 + 2

lyudmila [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The amount of time, in hours, babies spent sleeping in two different nurseries is shown on the dot plots below.

azamat

Answer:

The babies in Nursery 2 spent more time napping.

Step-by-step explanation:

i had took a test and got it right

4 0

2 years ago

Read 2 more answers

PLEASE HELP

dsp73

Answer:

All events are independent

Step-by-step explanation:

You are given the table

$\begin{array}{cccc}&\text{Chocolate}&\text{Vanilla}&\text{Total}\\\text{Adults}&0.21&0.39&0.60\\\text{Children}&0.14&0.26&0.40\\\text{Total}&0.35&0.65&1.00\end{array}$

Two events A and B are independent when

$Pr(A\cap B)=Pr(A)\cdot Pr(B)$

a) A="Chocolate"

B="Adults"

A and B="Chocolate and Adults"

$Pr(A)=0.35\\ \\Pr(B)=0.60\\ \\Pr(A\cap B)=0.21$

Since $0.35\cdot 0.60=0.21$ events are independent

b) A="Children"

B="Chocolate"

A and B="Children and Chocolate"

$Pr(A)=0.40\\ \\Pr(B)=0.35\\ \\Pr(A\cap B)=0.14$

Since $0.40\cdot 0.35=0.14$ events are independent

c) A="Vanilla"

B="Children"

A and B="Vanilla and Children"

$Pr(A)=0.65\\ \\Pr(B)=0.40\\ \\Pr(A\cap B)=0.26$

Since $0.65\cdot 0.40=0.26$ events are independent

4 0

3 years ago

In a study about the relationship between marital status and job level, 8235 males at a large manufacturing firm reported their

Marina CMI [18]

Answer:

Answer:A)The conditional relative frequency among widowed employees of those widowed working at grade 2 or below= 28/42 = 66.67%

Step-by-step explanation:

Answer:A)The conditional relative frequency among widowed employees of those widowed working at grade 2 or below= 28/42 = 66.67%

Step-by-step explanation:

In a two way frequency table, conditional relative frequency is it’s a fraction that tells us how many elements of of a group have a certain characteristic.

Here In a study about the relationship between marital status and job level, 8,235 males at a large manufacturing firm reported their job grade (from 1 to 4, with 4 being the highest) and their marital status.

from the given two way frequency table,

Number of widowed employees at grade 1 =8

Number of widowed employees at grade 2=20

∴ Number of widowed employees at grade 2 or below=8+20=28

And the total widowed employees working =42

Now the conditional relative frequency among widowed employees of those widowed working at grade 2 or below=

Therefore, the conditional relative frequency among widowed employees of those widowed working at grade 2 or below= 28/42 = 66.67%

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8 0

2 years ago