The hurdle and runner form a right triangle (see attached picture) such that
sin(30°) = <em>h</em> / (5 ft)
and
cos(30°) = <em>x</em> / (5 ft)
where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So
<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft
<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft
Answer:
7.5 cm²
Step-by-step explanation:
Dimensions of the large ∆:
Dimensions of the small ∆:
Difference between the area of the large and the small ∆ = 13.5 - 6 = 7.5 cm²
Is greater than or equal to $.00
Answer:
21 inches.
Step-by-step explanation:
From the question, we are given the following parameters or data or information: The legs of the triangles are 10 inches and 17 inches, perimeter of the rectangle is 146 units and length of the base for both triangles is 16 inches long.
Step one: the first step to do in this question is to determine or Calculate the value for the height of the smaller triangle.
Thus, 10^2 = (16/2)^2 + (b1)^2.
b1 = √ (100 - 64) = √ 36 = 6.
Step two: the second step to do in this question is to determine or Calculate the value for the height of the bigger triangle.
17^2 = (16/2)^2 + (b2)^2.
b2 = √ (289 - 64) = √ 225 = 15.
Step three: this is the lat step and it involves the addition of our values in step one and two above, that is;
6 + 15 = 21.
Thus, length of the kite’s other diagonal = 21 inches.
