<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
Answer:
50
Step-by-step explanation:
2(Mr stack's speed) = Coach Pugh's speed - 5mph
Mr stack's speed = (105mph - 5mph)/2
Mr stack's speed = 100mph/2
Mr stack's speed = 50mph
Answer:
Option A.
Step-by-step explanation:
The given equation is
Liliana wants to write an equivalent expression.
It can be written as
Using commutative property, we get
Using associative property, we get
Using distributive property, we get
Using addition property, we get
Therefore, the correct option is A.
7/28 = 25/x
x = (25 × 28)/7
x = (25 × 4)
x = 100
124 x 9 = the amount of girls which is 1116 then add the boys which is 124 so 1116 + 124 = 1250. After i did that i relized your question dont make sense