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3 years ago

Find the measurement of angle 2

Mathematics

2 answers:

leonid [27]3 years ago

5 0

Step-by-step explanation:

$< 1 = 62 \\$

by linear pair

$< 2 = 45$

by angle sum property

$\infty \pie \gamma \beta \alpha \pi\pi\pi\pi\pi\pi \sin( \cos( \tan( \cot( \sec( \sec( \csc( log_{ log( ln(?) ) }(?) ) ) ) ) ) ) )$

olasank [31]3 years ago

3 0

2=45 I believe so I think

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Given the functions m(x) = 4x − 11 and n(x) = x − 10, solve m[n(x)] and select the correct answer below. (2 points)

Citrus2011 [14]

For this case what we must do is a composition of functions which will be given by:
m (x) = 4x - 11
n (x) = x - 10
We have then:
m [n (x)] = 4 (x - 10) - 11
Rewriting the function:
m [n (x)] = 4x - 40 - 11
m [n (x)] = 4x - 51
Answer:
a. m [n (x)] = 4x - 51

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3 years ago

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TiliK225 [7]

Answer:

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Step-by-step explanation:

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4 years ago

What does 3/216 simplify to

quester [9]

216 divided by 3 is 72 so making the answer

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4 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago

As a nurse, part of your daily duties is to mix medications in the proper proportions for your patients. For one of your regular

spayn [35]

Answer:

10 milligrams of Medication A

Step-by-step explanation:

We'll write proportions/ratios for this:

20:16 is the usual proportion, and x:8 is this week's dose. The ratio from A to B has to be equal, so

20/16 = x/8

Cross-multiply:

(20)(8) = (16)(x)

160 = 16x

divide both sides by 16

x = 10

Please let me know if you have questions about this answer.

5 0

4 years ago