Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,
Thus, the required equation of the line is y=x-8.
Answer: q=16
Step-by-step explanation:
if we suppose q=16
(q+4)/2=10
Answer:
x = (4 + 2√34)/10, x = (4 - 2√34)/10
Step-by-step explanation:
5x² - 4x = 6
Subtract: 5x² - 4x - 6 = 0
Quadratic formula: x = (4 ± √(16 - 4*5*(-6)))/10
Multiply: x = (4 ± √(16 + 120))/10
Simplify: x = (4 ± 2√34)/10
In trigonometry, the right triangle is considered a special triangle because there are derived equations solely for this type. It is really convenient when dealing right triangle problems because it is more simplified courtesy of the Pythagorean theorems. It is derived that the square of the hypotenuse (longest side of the triangle) is equal to the sum of the squares of the other two legs. In equation, that would be c² = a² + b². For this activity, all you have to do is find the sum of the squares in columns a and b. Then, see if this is equal to the square of the values in column c. Let's calculate each row:
Row 1:
3² + 4² ? 5²
25 ? 25
25 = 25
Row 2:
5² + 12² ? 13²
169 ? 169
169 = 169
Row 3:
9² + 12² ? 15²
225 ? 225
225 = 225
Therefore, all of the given values conform to a² + b² = c².
2(2x+3)+(5x+4) simplified would be 4x+6+5x+4 and if you add those together you get 9x+10. Hope I helped! if you have any questions just leave a comment
