12 ÷ 5 = 2.4. So there will be 0.4 string left.
12 x 10000 = 120000
8 x 1000 = 8000
14 x 100 = 1400
7 x 1 = 7
120000 + 8000 + 1400 + 7
129407 is your answer
hope this helps
Suppose

is the number of possible combinations for a suitcase with a lock consisting of

wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for

wheels, or

is given recursively by the formula

starting with

(because you can start the combination with any one of the ten available digits 0 through 9).
For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).
By substitution, you have

This means a lock with 55 wheels will have

possible combinations (a number with 53 digits).
<span>-2x^2-x+7=0
Variable with the highest degree's (exponent) constant, -2 is a, next variable's constant, -1 is b, the constant or number without a variable, 7 is c
using substitution put the numbers into the formula
</span>(-b±√(b^(2)-4ac))/(a^(2))
(-(-1)±√((-1)^(2)-4(-2)(7))/((-2)^(2)) simplify
(1±√(1+56))/4
1±√(57)/4 is your answer
Two miles every 5 minutes.
Sorry i answered so late.