Answer
____________________________________________________________
This would be 21.5π * 360 / 20 yd^2 = 1215.18 yd^2 ( using pi = 3.14)
____________________________________________________________
Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so
- The length of the fencing is 80 meters, so
Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:
Then substitute for y in the first:
b) To maximize A, find the zero of the first derivative:
So y = (80-40)/2 = 20 meters.
For this case, the first thing we should do is use the following equation:
x ^ 2 + x-30
Here, we substitute the value of x = 20
We have then:
(20) ^ 2 + (20) -30 = 390 m ^ 2
Answer:
the area of the land when the length of the dentist's office is 20 meters is:
390 m ^ 2
Let the Length be L and the Width be W
The area is 8 cm²
LW = 8
The perimeter is 12
2(L + W) = 12
L + W = 6
Solve L and W:
LW = 8 --------------- (1)
L + W = 6------------ (2)
Equation (2):
L + W = 6
L = 6 - W -------------- Sub into (1)
(6 - W) W = 8
6W - W² = 8
W² - 6W + 8 =0
(W -2 )(W - 4) = 0
W = 2 or 4
When W =2, L = 6 - 2 = 4
When W = 4, L = 6 - 4 = 2
Answer: The Width is 2 cm and the Length is 4 cm
