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Elden [556K]
2 years ago
14

Simplify the expression: (9x+10) - (3x+7)

Mathematics
2 answers:
Nadya [2.5K]2 years ago
5 0

Answer: The answer to this problem would be (6x+3).

Step-by-step explanation:

All you have to do is take 9x+10 and subtract like terms. So you do 9x-3x and 10-7. You put it together and you will get (6x+3).

natali 33 [55]2 years ago
4 0

Answer:

6x+3

Step-by-step explanation:

You first must distribute the negative sign to 3x+7, giving you -3x+7. Then you combine like terms (the 9x+(-3x) and 10+(-7)). This would give you 6x+3

You might be interested in
Shannon walks 2,500 metres in 1 hour 40 minutes. <br> How far does she walk in one minute?
stich3 [128]

Answer:

25m

Step-by-step explanation:

Shannon's rate is 2,500m/100min. Simplifying, we see that this is equal to 25m/1min.

So, she walks 25 m in one minute.

4 0
2 years ago
Malliki Williams earned a $48,000 from royalties on her cookbook.She paid a 28% income tax on these royalties. The balance wasin
Nikitich [7]

Answer:

$20000 and $14560

Step-by-step explanation:

First, we need to get the total tax paid by Malliki Williams

To get that, we have to multiply her income tax (28%) by total royalties ($48000)

28% of $48000 = $13440

Balance after tax = $48000 - $13440

Balance = $34560

She invested some of the balance ($34560) at the rate of

3.25% ---- First investment

1.75% --- Second investment

Assume her first investment is x dollars

Definitely, her second investment would be $34560 - x

3.25% of x + 1.75% (34560 - x ) = 904.8

0.0325x + 0.0175(34560-x) = 904.8 ----- Open the bracket

0.0325x + 604.8x - 0.0175x = 904.8 ------ Collect like terms

0.0325x -0.0175x =904.8 - 604.8

0.015x = 300 ------ Divide both sides by 0.015

x = 300/0.015

x = 20000

Remember that x represents her first investment

Her second investment is $34560 - $20000 =$14560

4 0
3 years ago
2.c)in the diagram below, 4 m and ORIST at R. 5 $ 0 If m_1 = 63, find m_2.
pickupchik [31]

Data:

l and m are parallel lines

QR and ST are perpendicular in R

Angle 1 is 63°

The angle formed by perpendicular lines is a right angle (90°)

Angles 1 and 3 are alternate angles: angles that occur on opposite sides of a transversal line that is crossing two parallel.

Alternate angles are congruent, have the same measure.

\begin{gathered} m\angle1=m\angle3 \\  \\ m\angle3=63 \end{gathered}

The sum of the interior angles of a triangle is always 180°. In triangle QRT:

\begin{gathered} m\angle2+m\angle3+90=180 \\  \\ m\angle2+63+90=180 \\  \\ m\angle2+153=180 \end{gathered}

Use the equation above to find the measure of angle 2:

\begin{gathered} \text{Subtract 153 in both sides of the equation:} \\ m\angle2+153-153=180-153 \\  \\ m\angle2=27 \end{gathered}Then, the measure of angle 2 is 27°

8 0
10 months ago
A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha
Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

  • The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
  • the radius r=5cm
  • Punch is being poured into the bowl
  • The height at which the punch is increasing in the bowl is \frac{dh}{dt} = 1.5
  • the exposed area is a circle, (since the bowl is a hemisphere)
  • the radius of this circle can be written as 'a'
  • what is being asked is the rate of change of the exposed area when the height h = 2 cm
  • the rate of change of exposed area can be written as \frac{dA}{dt}.
  • since the exposed area is changing with respect to the height of punch. We can use the chain rule: \frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}
  • and since A = \pi a^2 the chain rule above can simplified to \frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt} -- we can call this Eq(1)

Solution:

the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

\frac{da}{dt} = \frac{(r-h)(1.5)}{a}

and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

simplify,

\frac{dA}{dt} = 3 \pi (r-h)

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

5 0
2 years ago
6th grade math i dont understand!!!!!!
Tema [17]
Umm im older and I dont even understand that
5 0
2 years ago
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