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Free_Kalibri [48]

3 years ago

15

The school media specialist has catalogue 2/3 of the new books in a shipment. If she has catalogued 52 books, what is the total

number of books in the shipment?

1 answer:

Vinil7 [7]3 years ago

5 0

Answer:

78 Books

Step-by-step explanation:

To answer the problem divide 52 by 2, then take the answer(26) and multiply by 3 which leads you to the 78.

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The abdominopelvic region that is bordered by all four imaginary lines is the

Ainat [17]

Umbilical point.

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4 0

3 years ago

Savatey [412]

Answer:

sorry

Step-by-step explanation:

plz send full question

7 0

3 years ago

GIVING 15 POINTS!!! PLEASE HELP

Lena [83]

1) |−11| = 11, therefore Peter is at a distance of 11 feet

2) Jimmy, because each of the two points is fraction 5 over 8 unit away from 0

3) 36 + 28=64 4x4=36+4x7=28 36+28=64

7+9=16 4x16=64

6 0

3 years ago

How many 12 x 12 pavers for 600 square feet?

34kurt

First, we calculate the area of one paver. This is:
12 x 12 = 144 square feet
Now, the number of pavers required may be determined by dividing the total surface area to be covered by the surface area of one paver, as:
number of pavers = 600 / 144
Number of pavers = 4.2

Because 0.2 pavers can not be obtained, 5 pavers are needed to completely cover 600 square feet.

5 0

3 years ago

Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B

Galina-37 [17]

Answer:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

8 0

3 years ago