What are the solutions to the equation (2x – 5)(3x – 1) = 0?
2 answers:
Answer:
x = 5/2 or x = 1/3
Step-by-step explanation:
Simplify
( 2 x − 5 )( 3 x − 1 ) .
6 x 2 − 17 x + 5 = 0
Use the quadratic formula to find the solutions.
or
Substitute the values a = 6 , b = − 17 , and c = 5 into the quadratic formula and solve for x .
17 ±sqrt(-17)^2-4*(6*5)
_________________
2*6
Simplify.
x = 17 ± 13 /12
The final answer is the combination of both solutions.
x = 5 /2 , 1 /3
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Answer:
Step-by-step explanation:
For the limit of a function to exist, then the right hand limit of the function must be equal to its left hand limit as shown;
If the function is f(x), for f(x) to exist then;
Given the function;
Lets check if the above statement is true.
The right hand limit of the function occurs at x> 9
f(x) = 9-x
The left hand limit occurs at x<9
f(x) = x+9
From the above calculation, it can be seen that , this shows that the function given does not exist at the given point.