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Tju [1.3M]
3 years ago
11

What are the solutions to the equation (2x – 5)(3x – 1) = 0?

Mathematics
2 answers:
Simora [160]3 years ago
8 0

x = 5/2 or x = 1/3

C is the answer.

bezimeni [28]3 years ago
5 0

Answer:

x = 5/2 or x = 1/3

Step-by-step explanation:

Simplify  

( 2 x − 5 )( 3 x − 1 ) .

6 x 2 − 17 x + 5 = 0

Use the quadratic formula to find the solutions.

\frac{-b+\sqrt{b^2-4ac} }{2a} or \frac{-b-\sqrt{b^2-4ac} }{2a}

Substitute the values  a = 6 ,  b = − 17 , and  c = 5  into the quadratic formula and solve for  x .

17 ±sqrt(-17)^2-4*(6*5)

_________________

2*6

Simplify.

x = 17 ± 13 /12

The final answer is the combination of both solutions.

x = 5 /2 ,  1 /3

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\large\begin{array}{l} \textsf{Find the domais of the rational function:}\\\\ \mathsf{C(x)=\dfrac{x-5}{x^2-25}}\\\\\\ \textsf{Denominators can't be zero:}\\\\ \mathsf{x^2-25\ne 0}\\\\ \mathsf{x^2\ne 25}\\\\ \begin{array}{rcl} \boxed{\begin{array}{rcl}\mathsf{x\ne -5}&~\textsf{ and }~&\mathsf{x\ne 5}\end{array}} \end{array} \end{array}


\large\begin{array}{l} \textsf{So the domain of C is}\\\\ \mathsf{D_C=\{x\in\mathbb{R}:~~x\ne -5~~and~~x\ne 5\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_C=\mathbb{R}\setminus\{-5,\,5\}}\\\\\\ \textsf{or in interval notation}\\\\ \mathsf{D_C=\left]-\infty,\,-5\right[\,\cup\,\left]-5,\,5\right[\,\cup\,\left]5,\,+\infty\right[\,.} \end{array}


\large\textsf{So pick up the one you prefer. They're equivalent ways}\\\textsf{to represent the domain.}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2184171


\large\textsf{I hope this helps. :-)}


Tags: domain rational function fraction denominator restriction algebra

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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David made a scale drawing of a mural he is going to paint. He used a scale of 1 cm=4ft. If the actual mural will be 16 feet lon
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Answer:

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we know that

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Answer:

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5 0
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Hope this helps! :)
6 0
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