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Tju [1.3M]
3 years ago
11

What are the solutions to the equation (2x – 5)(3x – 1) = 0?

Mathematics
2 answers:
Simora [160]3 years ago
8 0

x = 5/2 or x = 1/3

C is the answer.

bezimeni [28]3 years ago
5 0

Answer:

x = 5/2 or x = 1/3

Step-by-step explanation:

Simplify  

( 2 x − 5 )( 3 x − 1 ) .

6 x 2 − 17 x + 5 = 0

Use the quadratic formula to find the solutions.

\frac{-b+\sqrt{b^2-4ac} }{2a} or \frac{-b-\sqrt{b^2-4ac} }{2a}

Substitute the values  a = 6 ,  b = − 17 , and  c = 5  into the quadratic formula and solve for  x .

17 ±sqrt(-17)^2-4*(6*5)

_________________

2*6

Simplify.

x = 17 ± 13 /12

The final answer is the combination of both solutions.

x = 5 /2 ,  1 /3

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The total cost after tax to repair Deborah’s computer is represented by 0.09(60h)+60h, where h represents the number of hours it
tia_tia [17]

Answer:

0.09 OR 9% is her tax

Step-by-step explanation:

Deborah has to pay 9% for tax. So is someone worked on her computer for two hours then she pays 9% on $120 worth of work. So her tax amount would be $10.800 and her total amount would be 10.8 +120 = $130.80.

4 0
4 years ago
A bag contains red marbles, white marbles, and blue marbles. Randomly choose two marbles, one at a time, and without replacement
dsp73

Answer:

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

P(Same) = \frac{67}{210}

Step-by-step explanation:

Given (Omitted from the question)

Red = 7

White = 9

Blue = 5

Solving (a): P(First\ White\ and\ Second\ Blue)

This is calculated using:

P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)

P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}

<em>We used Total - 1 because it is a probability without replacement</em>

So, we have:

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}

P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}

P(First\ White\ and\ Second\ Blue) = \frac{45}{420}

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

Solving (b) P(Same)

This is calculated as:

P(Same) = P(First\ Blue\ and Second\ Blue)\or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)

P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})

P(Same) = (\frac{5}{21} * \frac{4}{20})+(\frac{7}{21} * \frac{6}{20})+(\frac{9}{21} * \frac{8}{20})

P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}

P(Same) = \frac{20+42+72}{420}

P(Same) = \frac{134}{420}

P(Same) = \frac{67}{210}

6 0
3 years ago
Kinnear Plastics manufactures various components for the aircraft and marine industry. Kinnear buys plastic from two vendors: Ta
Goshia [24]

Answer:

Tappan    is $1400      

Hill             is  $1420

Step-by-step explanation:

Particulars                                      Tappan             Hill

Tons purchased                             4500            7500

Tons discarded                                135                 375

% plastic discarded                             3%               5%

% plastic accepted for                           97%             95%

Quoted price                                             1358           1349

% accepted for                                            97%              95%

Effective cost per ton

= Quoted price / % accepted for

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Effective cost per ton

Tappan          Hill

$1400              $1420

7 0
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24) -10 to 25 

25) 42

26) to much

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don't get mad, this was only for 13 points so that's on you

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4 years ago
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Provide the graph and I would be happy to help :)
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