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Salsk061 [2.6K]
3 years ago
10

Write the Roman Numeral CLXIV in standard form. Roman Numeral Standard Number 1 5 10 50 100 500 1,000 X L C D A) 169 B) 166 C) 1

64​
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

164

Step-by-step explanation:

in standard form CLXIV IS 164

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(sqrt3-sqrt3i)^4
Ludmilka [50]

The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

<h3>Absolute values of the complex numbers</h3>

The absolute values of the complex numbers are determined as follows;

(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

|z| = \sqrt{(\sqrt{3} )^2 + (\sqrt{3 }\times1 )^2} } \\\\|z| = \sqrt{6}

(-1+sqrt3i)^12 = (-1 + √3i)¹²

|z| = \sqrt{(-1)^2 + (\sqrt{3)^2} } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt 3-i)^6 = (√3 - i)⁶

|z| = \sqrt{(\sqrt{3})^2 + (-1)^2 } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

|z| = \sqrt{(\sqrt{2} )^2 + (\sqrt{2})^2 } \\\\|z| = 2

(sqrt2-i)^6 = (√2 - i)⁶

|z| = \sqrt{(\sqrt{2})^2 + (-1)^2} } \\\\|z| = \sqrt{3}

Increasing order of the complex numbers;

(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

Learn more about complex numbers here: brainly.com/question/10662770

#SPJ1

3 0
3 years ago
What is an addition equation for 20-(-10)?
noname [10]

Answer:

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Step-by-step explanation:

You are subtracting a negative so it becomes like that.

5 0
3 years ago
Use the product of powers property to simplify the numeric expression.
motikmotik

Answer:

The value of 4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}  is  4^{\dfrac{8}{15}} .

Step-by-step explanation:

We need to simplify the numeric expression using property. The expression is as follows :

4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}

The property to be used is : x^a{\cdot} x^b=x^{a+b}

This property is valid if the base is same. Here, base is x.

In this given problem, x = 4, a = 1/3 and b = 1/5

So,

4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}}=4^{\dfrac{1}{3}+\dfrac{1}{5}}\\\\=4^{\dfrac{5+3}{15}}\\\\=4^{\dfrac{8}{15}}

So, the value of 4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}  is  4^{\dfrac{8}{15}} .

8 0
4 years ago
Solve the following for the variable for 180-x=3(90-x)
lara31 [8.8K]
X = 45 is the answer
180-x = 3(90-x)
=> 180-x = 270 - 3x
=> -x+3x = 270-180
=> 2x = 90
=> x = 90/2
=> x = 45
Please mark brainliest.
Have good day :)
6 0
3 years ago
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