Let the numbers be x and y. Then xy = -30 and x+y = -3.
Solve xy = -30 for y: y = -30/x
subst. -30/x for y in x+y= -3: x - 30/x = -3
Multiply all 3 terms by x: x^2 - 30 = -3x, so x^2 + 3x - 10 = 0
Solve this quadratic equation for x. x: {-5, 2}
If x = -5, then x+y = -3 becomes -5 + y = -3, and y = 2.
You should check to determine whether x=2 is also correct. If it is, what is the corresponding y value?
It’s b here is proof of what i got
Answer:
2 
Step-by-step explanation:
The absolute value of a number is the value of x (the number) without a negative, 2 and a third is already positive, so that is the answer :D
Hope this helps, good luck! :)
Answer:
There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.
It would be unusual to randomly select a person aged 40 years or older who is male and jogs.
Step-by-step explanation:
We have these following probabilities.
A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so
.
In addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male.
is the probability that the person is a male, given that he/she jogs. So 
The Bayes theorem states that:

In which
is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.
So

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.
A probability is unusual when it is smaller than 5%.
So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.
Answer:
y = 4
Step-by-step explanation:
8(y+4)-2(y-1)=70-3y
8y+32-2y+2=70-3y
Grouping of like terms
8y-2y+3y=70-32-2
9y=36
Divide both sides by 9
9y/9 = 36/9
9 cancels itself and 9.
y=36/9
y=4
Therefore, y = 4.
Hope it helps.
If so, mark as brainliest.