Answer:
21 consonant tiles
Step-by-step explanation:
Henry has a bag containing 39 letter tiles, some consonants, and some vowels.
He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?
Step 1
We add up the number of tiles that he pulls out of the bag
= 7 consonant tiles + 6 vowel tiles
= 13 tiles
Step 2
We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag
= 39 tiles ÷ 13 tiles
= 3
Step 3
The most likely number of consonant tiles in Henry's bag is calculated as:
3 × The number of consonant tiles that was pulled out of the bag.
Hence:
3 × 7 consonant tiles
= 21 consonant tiles.
Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.
Answer:
2i - (-3 + i)
Step-by-step explanation:
I think this is it. Sorry if it's wrong
Answer: 
Step-by-step explanation:
All that is required here is to substitute x = 2x into the right side in the same way that is done for a numeric value.
Answer:
See below.
Step-by-step explanation:
This is how you prove it.
<B and <F are given as congruent.
This is 1 pair of congruent angles for triangles ABC and GFE.
<DEC and <DCE are given as congruent.
Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.
This is 1 pair of congruent angles for triangles ABC and GFE.
Now you need another side to do either AAS or ASA.
Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.
Now you have 1 pair of included sides congruent ABC and GFE.
Now using ASA, you prove triangles ABC and GFE congruent.
