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3 years ago

Any one know geometry please help me out

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

7 0

Answer:

X = 4

Step-by-step explanation:

And then the nearest tenth would be 0

cause all numbers that have 4 round to like 0 or the tenth under it. If it has a five or higher it rounds to 10 or the number above it

Vera_Pavlovna [14]3 years ago

3 0

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the trigonometry.

Here, since the triangle is right angles, with perpendicular = x and hypotenuse = 14 , and one angle = 25°

to get the value of x, we use the sine ratio.

hence, Sin(25°) = x/14

hence, x = sin(25°)*14 ==> 5.90

hence the value of x = 5.90 units.

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3 years ago

The value pi/2 is a solution for the equation 2sin^2 x -sinx-1=0

nikklg [1K]

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7 0

3 years ago

Identify which line from the graph the following right triangles could lie on.

qaws [65]

Answer:

Step-by-step explanation:

Slope of line A = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{9}{3}$

= 3

Slope of line B = $\frac{9}{6}$

= $\frac{3}{2}$

Slope of line C = $\frac{6}{8}$

= $\frac{3}{4}$

5). Slope of the hypotenuse of the right triangle = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{90}{120}$

= $\frac{3}{4}$

Since slopes of line C and the hypotenuse are same, right triangle may lie on line C.

6). Slope of the hypotenuse = $\frac{30}{10}$

= 3

Therefore, this triangle may lie on the line A.

7). Slope of hypotenuse = $\frac{18}{24}$

= $\frac{3}{4}$

Given triangle may lie on the line C.

8). Slope of hypotenuse = $\frac{21}{14}$

= $\frac{3}{2}$

Given triangle may lie on the line B.

9). Slope of hypotenuse = $\frac{36}{24}$

= $\frac{3}{2}$

Given triangle may lie on the line B.

10). Slope of hypotenuse = $\frac{48}{16}$

= 3

Given triangle may lie on the line A.

7 0

3 years ago

Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0

MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂= ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂= ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ = - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0

3 years ago

3x + 10y = 12, 3x - 8y = 12

weeeeeb [17]

Working attached below:

Hope this helps! Any questions let me know :)

6 0

2 years ago