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In-s [12.5K]
2 years ago
8

On a nearby pond, black and white ducks are swimming in groups of three. James wants to find the experimental probability of two

white ducks and one black duck swimming together. Design a simulation using a coin flip and explain why it is the best choice for James.
Mathematics
2 answers:
Elza [17]2 years ago
8 0

Answer:

Step-by-step explanation:

NeTakaya2 years ago
3 0

Answer:

There are only two choices, a black or white duck, so a coin is the best choice. To represent a set of possible outcomes, toss the coin three times. Repeat the experiment multiple times. To find the probability, divide the observed desired outcomes by the total number of trials.

Step-by-step explanation:

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Find all real eighth roots of 72.089. Round to the nearest thousandth
Svetradugi [14.3K]
I would say that <span> <span> <span> 1.7070004089  </span> </span> </span> is the only eighth root of 72.089.

72.089^(1/8) = <span> <span> <span> 1.7070004089 </span> </span> </span>

6 0
3 years ago
A rope 40m long is used to form a rectangle. If the length of the rectangle formed is 4m longer than the width. Calculate the ar
ivanzaharov [21]

Answer:

96 sq. m

Step-by-step explanation:

If the width is x, the length is x + 4 and since perimeter = 2 * (length + width), we can write:

40 = 2(x + x + 4)

40 = 2(2x + 4)

20 = 2x + 4

16 = 2x

x = 8 so x + 4 = 12, therefore the area is 8 * 12 = 96 square meters.

5 0
2 years ago
Read 2 more answers
Joe is making a recipe that calls for 3/4 teaspoon of cinnamon. His only measuring spoon holds 1/8 teaspoon. How many times will
allochka39001 [22]
He will need to fill his measuring cup 8 times
6 0
3 years ago
Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
3 years ago
Emergency question! please help
Elis [28]

Answer:

2 double stuffed oreos that have 150 calories has more calories if you add that up its 300

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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