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3 years ago

(8x3 - 30x + 21) / (4x -6)

Mathematics

2 answers:

abruzzese [7]3 years ago

5 0

Answer:

$\frac{ {8x}^{3} - 30x + 21 }{2(2x - 3)}$

Step-by-step explanation:

1) Factor out the common terms 2.

$\frac{8x^{3} - 30x + 21}{2(2x - 3)}$

Therefor, the answer is 8x³ - 30x + 21 / 2 ( 2x - 3 ).

guajiro [1.7K]3 years ago

5 0

Answer:

8x3 - 30x + 21

————————

2 • (2x - 3)

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "x3" was replaced by "x^3".

8x3 - 30x + 21

Simplify —————————

4x - 6

Pull out like factors :

4x - 6 = 2 • (2x - 3)

Find roots (zeroes) of : F(x) = 8x3 - 30x + 21

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 8 and the Trailing Constant is 21.

The factor(s) are:

of the Leading Coefficient : 1,2 ,4 ,8

of the Trailing Constant : 1 ,3 ,7 ,21

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 43.00

-1 2 -0.50 35.00

-1 4 -0.25 28.38

-1 8 -0.12 24.73

-3 1 -3.00 -105.00

Note - For tidiness, printing of 27 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Polynomial Long Division

Dividing : 8x3 - 30x + 21

("Dividend")

By : 2x - 3 ("Divisor")

dividend 8x3 - 30x + 21

- divisor * 4x2 8x3 - 12x2

remainder 12x2 - 30x + 21

- divisor * 6x1 12x2 - 18x

remainder - 12x + 21

- divisor * -6x0 - 12x + 18

remainder 3

Quotient : 4x2 + 6x - 6

Remainder : 3

Answer: 8x3 - 30x + 21

————————

2 • (2x - 3)

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6 0

3 years ago

One number is 6 more than anouther number. the sum of their squares is 90

Flura [38]

Let x = greater number
      y = smaller number

(1) $x = y + 6
$
(1) $y = x-6$

(2) $x^{2} + y^{2} = 90$
We'll substitute y in (1) to (2)
(2) $x^{2} + (x-6)^{2} = 90$
   $x^{2} + (x^{2} - 12x + 36) = 90$
   $x^2 + x^2 -12x + 36 - 90 = 0$
   $2x^2 - 12x -54 = 0
$
   $2(x^2 - 6x - 27) = 0$
   $2(x - 9)(x + 3) = 0$
x - 9 = 0 or x + 3 = 0
      x = 9 x = -3
and
y = x - 6 y = x - 6
y = 9 - 6 y = -3 - 6
y = 3 y = -9

Therefore, the two numbers can be 9 and 3 or -3 and -9.

6 0

3 years ago

The temperature in the freezer is -15°C. The temperature outside the freezer is 10°C. Find the difference between these two temp

gizmo_the_mogwai [7]

Answer:

Yes it is 25

Step-by-step explanation:

10 - 25 = -15

-15 + 25 = 10

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2 years ago

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Nina [5.8K]

Answer:

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Step-by-step explanation:

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3 years ago

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iris [78.8K]

Answer:

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step by step explaination:

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3 years ago

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