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Paha777 [63]
3 years ago
13

Two phone companies one is 11/+.16/ min And another is 20+.11/min How many minutes will make both equal amounts

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

Company one charges $11 + $0.16 per min.

Then if you talk for x minutes, the cost will be:

C₁(x) = $11 + ($0.16 per min)*x

For company two, the prize is $20 + $0.11 per min, and if yo talk for x minutes, the cost will be:

C₂(x) = $20 + ($0.11 per min)*x

Now we want to find the value of x, the number of minutes, such that the cost is the same with both companies.

C₁(x) = C₂(x)

$11 + ($0.16 per min)*x = $20 + ($0.11 per min)*x

($0.16 per min)*x - ($0.11 per min)*x = $20 - $11

($0.05 per min)*x = $9

x = $9/($0.05 per min) = 180 mins

If you speak for 180 minutes, the cost is the same in both companies.

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1) 2x – y = 1
aleksandrvk [35]

Answer:

1) (2, 3)

2) (2, -5).

Step-by-step explanation:

2x – y = 1

2x +2y = 10   Subtract to eliminate  the 2x:

2x - 2x - y - 2y = 1  - 10

-3y = -9

y = 3.

Plug this into the first equation:

2x - 3 = 1

2x = 4

x = 2.

2)

5x – y =15

x + y = -3     Adding to eliminate y:

5x + x - y + y = 15 + -3

6x = 12

x = 2

Plug this into the first equation:

5(2) - y = 15

-y = 15 - 10 = 5

y = -5.

6 0
3 years ago
Help, please!! I need the answer
Lorico [155]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
Order these numbers from least to greatest. 4811 , 4.626 , 5.63 , 9320
scoundrel [369]
4.626,5.63,4811,9320.........
8 0
4 years ago
Please anyoneeeeeeee.....i am almost done just please help me
Vitek1552 [10]

\boxed{\sf \overrightarrow{XV}\:and\:\overrightarrow{XY}}

\Large{\underline{\sf Observations:-}}

Option:-1

Question asks to find opposite rays .Here the given options are segments so this is wrong.

Option-2

This is also given segments so its wrong

Option:-3

Question asks to find rays having endpoint x .means both started from one point and went different sides

So here Its v-x-y so its wrong.

7 0
3 years ago
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting. It is
yan [13]

Answer:

No, there is not sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting.

This means that the null hypothesis is:

H_{0}: \mu = 434

It is believed that the machine is underfilling the bags.

This means that the alternate hypothesis is:

H_{a}: \mu < 434

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

434 is tested at the null hypothesis:

This means that \mu = 434

A 9 bag sample had a mean of 431 grams with a variance of 144.

This means that X = 431, n = 9, \sigma = \sqrt{144} = 12

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{431 - 434}{\frac{12}{\sqrt{9}}}

z = -0.75

P-value of the test:

The pvalue of the test is the pvalue of z = -0.75, which is 0.2266

0.2266 > 0.01, which means that there is not sufficient evidence to support the claim that the bags are underfilled.

7 0
3 years ago
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