Given the differential equation v′′+3v′+4v=([cos(8∗t)]3)u(t)
1 answer:
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Answer: 918km^2
Step-by-step explanation:
Let x be the new dimension of the area;
The complete question is
<span>Bradley made a house for his dog, Bowser, out of wood with a cube base and a triangular prism top. The dimensions of the dog house are a = 2 feet, b = 1 foot, and c = 1.4 feet.
</span><span>If Bradley plans to paint the outside of the dog house blue, not including the bottom, how many square feet of paint will he use?
the picture in the attached figure
</span>
we know that
surface area of the figure=surface area of cube+surface area of triangular prism
surface area of cube=4*a²----> 4*2²-----> 16 ft²
surface area of triangular prism=2*[a*c]+2*[a*b/2]---> 2*[2*1.4]+[2*1]
surface area of triangular prism=5.6+2----> 7.6 ft²
surface area of the figure=16 ft²+7.6 ft²----> 23.6 ft²
the answer is
23.6 ft²
<span>Bradley made a house for his dog, Bowser, out of wood with a cube base and a triangular prism top. The dimensions of the dog house are a = 2 feet, b = 1 foot, and c = 1.4 feet.
</span><span>If Bradley plans to paint the outside of the dog house blue, not including the bottom, how many square feet of paint will he use?
the picture in the attached figure
</span>
we know that
surface area of the figure=surface area of cube+surface area of triangular prism
surface area of cube=4*a²----> 4*2²-----> 16 ft²
surface area of triangular prism=2*[a*c]+2*[a*b/2]---> 2*[2*1.4]+[2*1]
surface area of triangular prism=5.6+2----> 7.6 ft²
surface area of the figure=16 ft²+7.6 ft²----> 23.6 ft²
the answer is
23.6 ft²