Answer:
I think that it is 1:2
Step-by-step explanation:
<u>Answer-</u>
<em>At 15.91° the ball was thrown.</em>
<u>Solution-</u>
<em>In the question it is given that the ball was released and caught from the same height.</em>
We know that,

Where,
R = Range of the projectile = 7.75 m,
u = Initial speed = 12 m/s
θ = Angle at which it was released
g = Acceleration due to gravity = 9.8 m/s²
Putting all the values,





Answer:
the percent increase is by 30%
Step-by-step explanation:
30% of 200 equals 60
X = 8.
2 (8) -4 = 12. LM=12