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lianna [129]
3 years ago
10

Write an equation in slope intercept form for the line that passes through (2,4) , x axis

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0

Answer:

Step-by-step explanation:

A line parallel to the x-axis is a horizontal line. A horizontal line will be in the form y = a constant. Since this line must pass through the point (4, 2), then the equation of the line is y = 2.

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What is y + 10 = -3(x + 10) in slope-intercept form?
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Y = -3x - 40. Use the distributive property to get the slope and move the 10 to the other side to isolate the y
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One factor of the polynomial 6x3 − x2 + 8x + 5 is (2x + 1). What is the other factor of the polynomial? (Note: Use long division
maria [59]

Answer:

(3x^2 - 2x + 5)

Step-by-step explanation:

3x^2 - 2x + 5

2x + 1 \sqrt{6 {x}^{3}  -  {x}^{2}  + 8x + 5  }

- <u>(6x^3 + 3x^2)</u>

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- <u>(-4x^2 - 2x)</u>

10x + 5

-(<u>10x + 5)</u>

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(2x+1) (3x^2 - 2x + 5) = 6x^3 - x^2 + 8x + 5

Therefore the other factor of the polynomial is (3x^2 - 2x + 5)

4 0
3 years ago
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What is the equation when y=5x+4 is reflected over the x-axis, y-axis &amp; y=x?
tigry1 [53]

Answer:

A) y=-5x-4

B) y=-5x+4

C) y=\frac{x-4}{5}

Step-by-step explanation:

So we have the equation:

y=5x+4

Let's write this in function notation. Thus:

y=f(x)=5x+4

A)

To flip a function over the x-axis, multiply the function by -1. Thus:

f(x)=5x+4\\-(f(x))=-(5x+4)

Simplify:

-f(x)=-5x-4

B) To flip a function over the y-axis, change the variable x to -x. Thus:

f(x)=5x+4\\f(-x)=5(-x)+4

Simplify:

f(-x)=-5x+4

C) A reflection over the line y=x is synonymous with finding the inverse of the function.

To find the inverse, switch x and f(x) and solve for f(x):

f(x)=5x+4

Switch:

x=5f^{-1}(x)+4

Subtract 4 from both sides:

x-4=5f^{-1}(x)

Divide both sides by 5:

f^{-1}(x)=\frac{x-4}{5}

And we're done :)

7 0
3 years ago
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