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lianna [129]
3 years ago
10

Write an equation in slope intercept form for the line that passes through (2,4) , x axis

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0

Answer:

Step-by-step explanation:

A line parallel to the x-axis is a horizontal line. A horizontal line will be in the form y = a constant. Since this line must pass through the point (4, 2), then the equation of the line is y = 2.

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What is a equation for line with a slope o 2/3 and a y-intercept of (0,0)
Lerok [7]

Answer:

y= 2/3 x

Step-by-step explanation:

point slope form

y-y1 = m(x-x1)

y-0 = 2/3 (x-0)

y = 2/3(x)

y= 2/3 x


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3 years ago
What is 25 5/10 x 3 as a mixed number?
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Answer:

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3 years ago
Allison wants to buy a game that costs $120. She has saved $30 for the game. She earns $5 per hour babysitting.
sergey [27]

Answer:

Step-by-step explanation:

<em>Cost of game = $120</em>

<em>Current savings = $30</em>

<em>Rate for babysitting (per hour) = $5/hour</em>

<em></em>

<em>So, required equation is :-</em>

<em>120 = 5h + 30</em>

<em>5h = 90</em>

<em>h = 18</em>

<em></em>

<em>She must make $90 by babysitting for 18 more hours.</em>

7 0
3 years ago
Read 2 more answers
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.
andreyandreev [35.5K]

The products of the polynomials are:

  • (xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
  • (2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
  • (x - y) * (x + 3y) = x² + 2xy + 3y²
  • (xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18
  • (x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6
  • (x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

<u>Pair 1: (xy + 9y + 2) and (xy – 3)</u>

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

<u>Pair 2: (2xy + x + y) and (3xy² - y)</u>

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

<u>Pair 3: (x – y) and (x + 3y) </u>

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

<u>Pair 4: (xy + 3x + 2) and (xy – 9) </u>

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9)  = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18

<u>Pair 5: (x² + 3xy - 2) and (xy + 3) </u>

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6

<u>Pair 6: (x + 3y) and (x – 3y)</u>

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

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iVinArrow [24]

Answer: 1 year old

Step-by-step explanation:

6 0
3 years ago
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