Answer:
-6 and 7
Step-by-step explanation:
It is useful to look at the factor pairs of -42.
-42 = -1(42) = -2(21) = -3(14) = -6(7)
Sums of these factor pairs are 41, 19, 11, 1.
You want the last pair of factors: -6 and 7.
To solve this system by substitution, we must substitute in the value we are given for x in terms of y (the first equation) into the second equation. This is modeled below:
x = -8y - 15
2x + 5y = -8
2 (-8y - 15) + 5y = -8
Now, we should solve this new equation for y. To begin, we should use the distributive property to get rid of the parentheses on the left side of the equation and begin the simplification process.
-16y - 30 + 5y = -8
Next, we can combine like terms on the left side of the equation by adding together the two terms that both contain the variable y.
-11y - 30 = -8
Next, we should add 30 to both sides in order to move all of the constant (number) terms to the left side of the equation.
-11y = 22
After that, we should divide both sides of the equation by -11 in order to get the variable y alone.
y = -2
Now, we can substitute our value for y back into one of our original equations (it doesn't matter which one you choose; they will yield the same answer).
x = -8y - 15
x = -8(-2) - 15
To simplify, we should following the order of operations outlined by PEMDAS and compute the multiplication and then the subtraction.
x = 16 - 15
x = 1
Therefore, the answer to the system is x = 1 and y = -2, or (1,-2) when written as an ordered pair.
Hope this helps!
Answer:
Option C
Step-by-step explanation:
2 pentagons and 5 rectangles are needed to build this pentagonal prism!
i) The given function is
The domain is all real values except the ones that will make the denominator zero.
The domain is all real values except, x=2.5.
ii) To find the vertical asymptote, we equate the denominator to zero and solve for x.
iii) If we equate the numerator to zero, we get;
This implies that;
iv) To find the y-intercept, we put x=0 into the given function to get;
.
.
.
v)
The degrees of both numerator and the denominator are the same.
The ratio of the coefficient of the degree of the numerator to that of the denominator will give us the asymptote.
The horizontal asymptote is 
.
vi) The function has no common factors that are at least linear.
The function has no holes in it.
vii) This rational function has no oblique asymptotes because it is a proper rational function.
