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scoundrel [369]
3 years ago
14

Construct a frequency polygon that represents the following data regarding the selling prices of houses sold in 2006 for a parti

cular neighborhood find the midpoint
Class Frequency
78787 – 98786 9
98787 – 118786 8
18787 – 138786 9
138787 – 158786 4
158787 – 178786 8
Mathematics
1 answer:
Rashid [163]3 years ago
4 0

Answer:

See attachment for polygon

Step-by-step explanation:

Given

\begin{array}{cc}{Class} & {Frequency} & 78787 - 98786 & 9 &98787 - 118786 & 8 & 118787 - 138786 & 9 & 138787 - 158786 & 4 & 158787 - 178786 & 8 \ \end{array}

Required

The frequency polygon

First, we calculate the midpoint of each class.

This is the average of the class limits

So, we have:

x_1 = \frac{78787 + 98786}{2} =  \frac{177573}{2} = 88786.5

x_2 = \frac{98787 + 118786}{2} =  \frac{217573}{2} = 108786.5

----

--

-

x_5 = \frac{158787 + 178786}{2} =  \frac{337573}{2} = 168786.5

(138787 + 158786)/2

So, the table becomes:

\begin{array}{ccc}{Class} & {Frequency} & {x} &78787 - 98786 & 9 & 88786.5 & 98787 - 118786 & 8 & 108786.5 & 118787 - 138786 & 9 & 128786.5 & 138787 - 158786 & 4 & 148787.5 & 158787 - 178786 & 8 & 168786.5\ \end{array}

<em>See attachment for frequency polygon</em>

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