It may be 1^4 ............................
Simplify square roots
find all the prime factors of the radicand
and group them in pairs
any factor that appears in a pair can be pulled out in front of the radical sign once for ever group of two that can be made.
Hope that help sorry if it doesn't make sense.. :( <3
Oh that’s so easy 6 grade math so I saw there’s no y intercept so just see where the point’s coordinates are
Solution: The factor form of the given polynomial is
.
Explanation:
To find the factor form of the given polynomial fisrt find the random value of x for which the vlaue of f(x) is 0.
The value of the function f(x) is 0 for
, therefore
is a factor of given function.
Use synthetic method to divide the given polynomial for by
. Write coefficients of polynomial in top line and -1 on left side of the line. Write first element in bottom line then multiply it by -1 and write it in second line below the element second element and the add. The division by synthetic method is given in figure 1.
The bottom line shows the coefficients of the quotient polynomial.
So 
Similarly
is the factor of given polynomial because for x=-2 the value of parenthesis polynomial is 0.
Use synthetic method to divide the parenthesis polynomial for by
. it is shown in figure 2.
So

Hence the factor form of the given polynomial is
. The graph of the given function is given in figure 3.