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3 years ago

Emily is giving candy to 8 of her friends. She wants to give each friend

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

8 0

Answer:

uhhh the question isn't clear but if she wants to give each friend 1 she'll need 8 chocolate bars. If she wants to give each friend 2 she'll need 16 and so on, I'll provide a multiplication table of 8.

8 x 1 = 8

8 x 2 = 16

8 x 3 = 24

8 x 4 = 32

8 x 5 = 40

8 x 6 = 48

8 x 7 = 56

8 x 8 = 64

8 x 9 = 72

8 x 10 = 80

8 x 11 = 88

8 x 12 = 96

ella [17]3 years ago

3 0

She needs 8 chocolate bars to be able to give each 8 of her friends one bar.

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P=f/a, where f=70 and a=20 f is increased by 10 a is increased to by 10

valina [46]

Answer:

P=3.5

P=2.667

Step-by-step explanation:

p=f/a

P=70/20

P=3.5

then f is increased by 10

f=70+10=80

and a is increased by 10

a=20+10

a=30

therefore; P=f/a

P=80/30

P=2.667

3 0

2 years ago

Last summer, Brianna planted 2 plants

Volgvan

Answer: how many square feet are there? multiple each square foot by 2

Step-by-step explanation:

4 0

3 years ago

Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a

Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

X = a person has the disease

P = the test result is positive

N = the test result is negative

Given:

$P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10$

Compute the value of P (P|X) as follows:

$P(P|X)=1-P(P|X^{c})=1-0.15=0.85$

Compute the probability of a positive test result as follows:

$P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22$

Compute the probability of a person having the disease given that he/she was tested positive as follows:

$P(X|P)=\frac{P(P|X)P(X)}{P(P)}=\frac{0.85\times0.10}{0.22} =0.3864$

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

3 0

3 years ago

A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco

sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

Let p = proportion of all cars in San Francisco who are blue

SO, Null Hypothesis, $H_0$ : p = 25% {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 600 cars in San Francisco who are blue = $\frac{141}{600}$ = 0.235

n = sample of cars = 600

So, test statistics = $\frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }$

= -0.866

Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0

3 years ago

The vertex of the parabola below is at the point (2, 4), and the point (3, 6) is on the parabola. What is the equation of the pa

Liula [17]

C and B are *candidates* for being the correct solution
because f(2) = 4 for both.

A is the correct solution because f(3)=6

4 0

3 years ago