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Anika [276]
2 years ago
12

I need help please!! Please answer with an explanation steps by steps please

Mathematics
1 answer:
Sonbull [250]2 years ago
3 0

Answer:

send me a message I think I can help

have a nice day

Step-by-step explanation:

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(No links please) I’ll mark Brainlyst
statuscvo [17]
18 bags of sand will be needed
3 0
3 years ago
Jordon missed 49 on his multiple choice math final and earned a grade of 65%. How many total questions were on the final exam?
harkovskaia [24]

Answer:

The exam was out of 75.

Step-by-step explanation:

You know that he earned 65% so more than half his answers were correct.

Then, you would guess and check try 49/60, 49/70, and go up by 10s or 5s. You will then realize that 49÷75 equals 65.333. This rounds up to 65.

8 0
2 years ago
Joelle has $15.75. She spent $6.38 at the store.
Alborosie
X + 6.38 = 15.75<span> would be the answer 
      x=9.37
for the first option, you are not adding 15.75 and x together. 
for the second option, it is correct, because in the problem, it is giving the operation, 15.75-6.38=x. when you turn it do inverse operation, you get </span><span>x + 6.38 = 15.75. 
for the third option, it doesn't make sense and it's not doing what the problem is asking for.
for the fourth option, you are not multiplying. you are subtracting </span>15.75 by<span> 6.38 to get x.</span>
4 0
3 years ago
Read 2 more answers
There were 6 friends who played a game of golf. Here were their scores. Player Score Sara -3 Steve 0 Kyle -2 Anna +3 Betsy +2 Mi
HACTEHA [7]

Answer: -4

Step-by-step explanation:

= -3 + 0 +(-2) + 3 + 2 +(-4)

= -3 - 2 + 3 + 2 - 4

= -4

6 0
4 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
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