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2 years ago

I need help please!! Please answer with an explanation steps by steps please

Mathematics

1 answer:

Sonbull [250]2 years ago

3 0

Answer:

send me a message I think I can help

have a nice day

Step-by-step explanation:

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(No links please) I’ll mark Brainlyst

statuscvo [17]

18 bags of sand will be needed

3 0

3 years ago

Jordon missed 49 on his multiple choice math final and earned a grade of 65%. How many total questions were on the final exam?

harkovskaia [24]

Answer:

The exam was out of 75.

Step-by-step explanation:

You know that he earned 65% so more than half his answers were correct.

Then, you would guess and check try 49/60, 49/70, and go up by 10s or 5s. You will then realize that 49÷75 equals 65.333. This rounds up to 65.

8 0

2 years ago

Joelle has $15.75. She spent $6.38 at the store.

Alborosie

X + 6.38 = 15.75 would be the answer
x=9.37
for the first option, you are not adding 15.75 and x together.
for the second option, it is correct, because in the problem, it is giving the operation, 15.75-6.38=x. when you turn it do inverse operation, you get x + 6.38 = 15.75.
for the third option, it doesn't make sense and it's not doing what the problem is asking for.
for the fourth option, you are not multiplying. you are subtracting 15.75 by 6.38 to get x.

4 0

3 years ago

Read 2 more answers

There were 6 friends who played a game of golf. Here were their scores. Player Score Sara -3 Steve 0 Kyle -2 Anna +3 Betsy +2 Mi

HACTEHA [7]

Answer: -4

Step-by-step explanation:

= -3 + 0 +(-2) + 3 + 2 +(-4)

= -3 - 2 + 3 + 2 - 4

= -4

6 0

4 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago