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3 years ago

HELP ME PLEASEEEEEEEEEEEEEEEE

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

3 0

Answer:

Assume the pair of dice are fair; if not, all bets are off!

Color one die green (G) and the other one red (R). There are 36 possibilities in throwing one green and one red die, eg (G1, R1), (G1, R2), etc; (G2, R1), (G2, R2), etc; etc; (G6, R1), (G6, R2), etc.

In the set of possible numbers from throwing a die, there are only 3 possibilities that sum to to 4: (G1, R3), (G2, R2), (G3, R1).

So the answer is 3/36, or one-twelfth.

1.3/36

2.7.9(8

Step-by-step explanation:

I dont know The Number 3 4 and 5 Sorry

ipn [44]3 years ago

3 0

Honestly the answer is 3/36

You might be interested in

Cone a has a radius of 6 units and a height of 4. Sphere B has the same volume as cone A. Find the Radius of sphere B.

postnew [5]

Answer:

3.3

Step-by-step explanation:

to determine the answer

calculate the volume of the cone

the volume of the cone = volume of the sphere

use the volume of the sphere to find the radius

Volume of a cone 1/3(nr^2h)

n = 22/7

r = radius

h = height

(1/3) x (22/7) x (6^2) x 4 = 150 .86

volume of sphere = (4/3) x (n) x (r^3)

n = 22/7

r = radius

(4/3) x radius^3 x (22/7) = 150.86

radius^3 = (3/4) x (7/22) x 150.86

radius^3 = 36

find the cube root of 36

radius = 3.3

37.71

6 0

3 years ago

Adena has a number cube whose sides are labeled 1 through 6. She rolls the number cube three times.

olga nikolaevna [1]

<span>On the first roll, the probability of rolling a 2 is 1/6. On the second roll the probability of rolling a 3 is also 1/6, and the probability of rolling a 4 on the third roll is, you guessed it, 1/6. Therefore the required probability is given by:
1/6 x 1/6 x 1/6 = 1/216</span>

5 0

3 years ago

Order form least to greatest -3/10, -4/15, -2/5

EleoNora [17]

Convert into decimal:

-3/10 = -0.3

-4/15 = -0.2667

-2/5 = -0.4

-0.4 < -0.3 < -0.267

-2/5 < -3/10 < -4/15

7 0

3 years ago

Read 2 more answers

11.

Artyom0805 [142]

Answer:

1. x= 12 y= 8 $\sqrt{3}$

2. x= 6 and y=6

3. x = 3 $\sqrt{3}$ y= 9

4. x=8 y= 8 $\sqrt{3}$

5. x =24 y= 12 $\sqrt{3}$

6. x=15 $\sqrt{2}$ y=15

7. y=15 x=10 $\sqrt{3}$

8. x =8 y= 8 $\sqrt{2}$

9. x =4 y= $\frac{8}{\sqrt{3} }$

10. z =10

11. x = 10

12. z=34

13. y=45

3 0

2 years ago

The manager of the zoo where the ticket price for an adult is $9.50 and the ticket price for a child is $6.50 wants to make at l

Y_Kistochka [10]

Answer:

$9.5x+6.5y\geq $800$

Step-by-step explanation:

9.5 in value of adult tickets. 6.5 is value of children's tickets. combined selling of all of them should be greater than or equal to 800 ("atleast" in the question shows it can be more but cannot be less)

4 0

3 years ago