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3 years ago

In - ABC shown below, side AC is extended to point D with mZ DAB = (180 – 3x) °,

Mathematics

1 answer:

Setler [38]3 years ago

4 0

Answer:

<BAC = 36degrees

Step-by-step explanation:

Find the diagram attached

The sum of the interior angle is equal to the exterior. Hence;

<B + <C = <DAB

6x+40 + x+20 = 180 - 3x

7x+60 = 180 - 3x

7x+3x = 180 - 60

10x = 120

x = 120/10

x = 12

Get <BAC

<BAC = 180 - (180-3x)

<BAC = 180-180+3x

<BAC = 3x

<BAC = 3(12)

<BAC = 36degrees

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Answer:

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3 years ago

Você precisa colocar suas renas, Raposa, Trovão, Cometa e Relâmpago, em uma fila única para puxar o seu trenó. No entanto, Comet

Gennadij [26K]

Answer:

If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.

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Step-by-step explanation:

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Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.

De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.

Espero que esto ayude :)

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3 years ago

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Likurg_2 [28]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Write the given expression as an algebraic expression in x. tan(2 cos^-1(x))

miv72 [106K]

$\bf tan\left[ 2cos^{-1}(x) \right]\implies tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]
\\\\\\
\textit{if we say }cos^{-1}\left( \frac{x}{1} \right)=\theta\textit{ that means }tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]\iff tan(2\theta)\\\\
-----------------------------\\\\
cos^{-1}\left( \frac{x}{1} \right)=\theta\implies cos(\theta)=\cfrac{x}{1}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}\\\\
-----------------------------\\\\
$

$\bf \textit{again, using the pythagorean theorem to get the opposite side}
\\\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\implies \pm\sqrt{1^2-x^2}=b
\\\\\\
\pm\sqrt{1-x^2}=b\\\\
-----------------------------\\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\cdot \frac{\pm\sqrt{1-x^2}}{x}}{1-\left( \frac{\pm\sqrt{1-x^2}}{x} \right)^2}
\\\\\\$

$\bf tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{1-\frac{1-x}{x}}\implies 
tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{\frac{x-1+x}{x}}
\\\\\\
tan(2\theta)=\cfrac{\pm2\sqrt{1-x^2}}{x}\cdot \cfrac{x}{2x-1}
\implies 
tan(2\theta)=\cfrac{\pm 2\sqrt{1-x^2}}{2x-1}$

6 0

3 years ago

A model car has a scale of 1:25. The length of the model when built is 9.6 in. What is the length of the actual car?

madreJ [45]

The length of the actual car is 240 inches

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Hope this helped you! :D

6 0

3 years ago