Question

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2 This answer is worth 100 point.

Answer 1

Answer:

32

Step-by-step explanation:

$(a+b)^2 = a^2 + 2ab + b^2$

$(a+b)^2 = a^2 + b^2 + 2ab$

$(a+b)^2=16+2(8)$

$(a+b)^2 = 16 + 16 = 32$