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tester [92]
3 years ago
7

I NEED HELP ASAP!!!!

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0
Answer is 4/7

You divide the length of C'D' over the length of CD
C'D'/CD = 8/14 = 4/7

The scale factor is smaller than 1, so C'D' is shorter than CD
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HELP AS SOON AS YOU CAN PLEASE ILL GIVE BRAINLIEST WHEN I CAN ​
Anni [7]

Answer:

SAS

Step-by-step explanation:

In triangle ABC and triangle EFD

1. BC = CD (S) Given

2. < BCD = < EFD (A) being vertically opposite. angles.

3. AC = CE (S) Given

Hence

By SAS postulate Triangle ABC and triangle EFD are congruent.

HOPE IT HELPS :)❤

8 0
3 years ago
Approximate: log 5 ^4/7
wolverine [178]

Do you mean the following:

log(5^(4/7))=around 0.4

log(5)^(4/7)=around 0.815

log(5^4)/7= same thing as top one

log((5^4)/7)=around 1.95

6 0
3 years ago
Read 2 more answers
Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.
S_A_V [24]
The answer is 4/1 you just have to divide 7 from both numbers and then you will get 4/1
3 0
2 years ago
Read 2 more answers
A triangular pyramid has these dimensions.
marishachu [46]

Answer: 42 cm3

Step-by-step explanation:

7 0
3 years ago
Math be like 0-0????
pashok25 [27]

Answer:  A & C

<u>Step-by-step explanation:</u>

HL is Hypotenuse-Leg

A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   a leg from ΔABC ≡ a leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

B) a leg from ΔABC ≡ a leg from ΔFGH

   the other leg from ΔABC ≡ the other leg from ΔFGH

   Therefore LL (not HL) Congruency Theorem can be used.

C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   at least one leg from ΔABC ≡ at least one leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

D) an angle from ΔABC ≡ an angle from ΔFGH

   the other angle from ΔABC ≡ the other angle from ΔFGH

   AA cannot be used for congruence.

5 0
3 years ago
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