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2 years ago

What is the inverse function of f(x) = -2? Hurry please

Mathematics

1 answer:

notsponge [240]2 years ago

4 0

Answer:

Step-by-step explanation:

2x/x-1

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75 = 17 ÷2×93871788=?<br>?÷748267818=?<br>?+7376818938÷7477818199×89=?

Alchen [17]

Answer:

YOUR MOM

Step-by-step explanation:

LOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLO)LOLOLOLOLLOllll

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3 years ago

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set. (

algol13

Answer:

its correct answer is

{y}

7 0

2 years ago

X^2+2x+1 is a perfect square trinomial <br><br> True of False?

Nimfa-mama [501]

Answer:

True.

Step-by-step explanation:

It is because it is in the form $a^2x^2+2abx+b^2$ and this equals $(ax+b)^2$ .

Why it is in that form: well comparing $a^2x^2+2abx+b^2$ , we have $a=1, b=1$ . Testing, plug in those values:

$(1)^2x^2+2(1)(1)x+(1)^2$

$1x^2+2x+1$

$x^2+2x+1$ .

This has the squared form of $(x+1)^2$ .

Test if you like:

$(x+1)^2$

$(x+1)(x+1)$

Use foil to expand:

First: x(x)=x^2

Outer: x(1)=x

Inner: 1(x)=x

Last: 1(1)=1

---------------Add together

$x^2+2x+1$

It does indeed equal.

4 0

2 years ago

Which student's work is correct? Explain please

Lunna [17]

Step-by-step explanation:

Wendy

-20 = x/2 + 7

-20 -7 = x/2 + 7 -7

-27 = x/2

-54 = x

x = -54

because it's math rule

8 0

2 years ago

What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1

Ratling [72]

Answer:

$\sqrt3$

Step-by-step explanation:

To find:

The value of $tan60^\circ$ = ?

Solution:

Kindly consider the equilateral $\triangle ABC$ as attached in the answer area.

Let the side of triangle = $a$ units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = $\frac{a}{2}$

Using Pythagorean Theorem in $\triangle ABD$ :

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}$

Side AD = $\frac{\sqrt3}{2}a$

Using Trigonometric ratio:

$tan\theta = \dfrac{Perpendicular}{Base}$

$tanB = \dfrac{AD}{BD}$

Putting the values of AD and BD:

$tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}$

5 0

2 years ago

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