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Sav [38]
3 years ago
12

Alonzo's suitcase can weigh no more than 20 kilograms if he wants to take it on the airplane without paying a fee. His suitcase

weighs 220 hectograms. How much weight will Alanzo have to take out of his suitcase to meet the weight limit?
Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Given: Alonzo's suitcase can weigh no more than 20 kilograms if he wants to take it on the airplane without paying a fee.

Let x denote the weight of suitcase, then

We know that 1 kg =10 hg

Therefore, 20kg=

⇒

Since, the weight of his suitcase is 220 hg.

The amount of weight will Alanzo have to take out of his suitcase to meet the weight limit will be :-

Hence, 20 hg of weight have to take out of his suitcase to meet the weight limit.

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Answer:

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Step-by-step explanation:

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Since r is a constant, it will be the same for any corresponding pairs of x and y. It is convenient to choose both x and y as integers, as in the third table entry.

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<em>Additional comment</em>

It is not a bad idea to check to see that this works with other values of x and y. For the first line of the table, we have x = 11:

  y = rx = (1/9)(11) = 11/9 = 1 2/9 . . . . matches the table value

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G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d
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By definition of covariance,


\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]


\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]


We have


\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]

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\mathbb E[cY-d]=c\mathbb E[Y]-d


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Putting everything together, we find the covariance reduces to


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3 years ago
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