Answer:
x=-3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
W=mg
<span>Where: </span>
<span>Weight = mass * acceleration due to gravity </span>
<span>So let's say I want to work out my weight on the moon. I know I weigh about 70kg (which would be N), but I can't use that figure for the calculation on the moon. That is what I weigh on Earth, so let's look at the equation... </span>
<span>70kg = mass * 9.81m/s^2 </span>
<span>Where 9.81m/s^2 is the acceleration due to gravity on the surface on the earth. I want to get rid of that, so let's work out my mass by division; </span>
<span>70/9.81 = 7.14kg </span>
<span>I googled the acceleration of gravity on the Moon, which was = 1.6m/s^2 </span>
<span>Let's use that in the same equation W=mg </span>
<span>W = 7.14kg * 1.6m/s^2 = 11.42N
</span><span>On the Moon, you would weigh approximately one sixth of your weight on Earth, so if your bathroom scales tell you you weigh 120 pounds, there you would weigh 20 pounds.
</span>
<span>Moon`s gravitational pull is about one-sixth to the gravitational pull on earth hence weight on moon is about one-sixth of the weight on earth.</span>
Answer:
I dont know if this will help or not but
Step-by-step explanation:
For this case, what you need to know is that to model this problem, you must use equations of the potential type:
y = A * (b) ^ t
Where:
A: initial population.
b: growth rate.
t: time.
Substituting values we have:
y = 15200 * (1.02) ^ t
After 10 years we have:
y = 15200 * (1.02) ^ 10
y = 18529
Answer:
An equation to model of the population growth is:
y = 15,200 ∙ 1.02 ^ x
the population after 10 years is:
about 18,529
