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Andreyy89
3 years ago
7

Find the area of obtuse triangle ABC when A=41 degrees, a=18cm, and b=22cm.

Mathematics
1 answer:
solniwko [45]3 years ago
5 0

Answer:

36 cm²

Step-by-step explanation:

  • cos A=  (`sqrt(b)` + `sqrt(c)` - `sqrt(a)`)/(2bc)

⇒c ≈ 5 cm

Sabc= (1/2)bcsin A ≈ 36 cm²

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Use the diagram to determine which statement is true
Dahasolnce [82]

The answer is d.

Finding area of ABCD :

  1. Find side length
  • side = √3² + 4²
  • side = 5

    2. Apply formula to find area

  • area = 5²
  • area = 25

Finding area of GHIA :

  • area = 4²
  • area - 16

Finding area of DEFG :

  • area = 3²
  • area = 9

Now, let's see whether is true.

  • Area (ABCD) - Area (GHIA) = Area (DEFG)
  • 25 - 16 = 9
  • 9 = 9

∴ Hence, it is proved √

7 0
2 years ago
Using the formula r=d/t where d is the distance in miles, r is the rate and t is the time in hours at which rate must you travel
valentina_108 [34]

r =  \frac{337.5}{4.5}  \\ r = 75
the answer is c-75mph
6 0
4 years ago
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there are 4 performers who will present their comedy acts this weekend at a comedy club. how many different ways are there to sc
DiKsa [7]
There should be 6 per number
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8 0
3 years ago
Given two angles in each triangle, how can you determine if two triangles are similar?​
goldenfox [79]

Answer:

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

Step-by-step explanation:

can you please mark me as brainliest

7 0
3 years ago
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I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
3 years ago
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