Find the area of obtuse triangle ABC when A=41 degrees, a=18cm, and b=22cm.
1 answer:
Answer:
36 cm²
Step-by-step explanation:
- cos A= (`sqrt(b)` + `sqrt(c)` - `sqrt(a)`)/(2bc)
⇒c ≈ 5 cm
Sabc= (1/2)bcsin A ≈ 36 cm²
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