A rhombus has 25-cm sides, and one diagonal is 14 cm long. How long is the other diagonal?
1 answer:
Let's visualize this problem (See the picture below). The red line represents the diagonal that is 14 cm, the green sides represent the 25-cm sides, and the yellow line represents the diagonal that we need to find. From this, you can see that the Pythagorean Theorem can be applied to this problem (Since the diagonals are perpendicular)
a^2+b^2=c^2
14^2+b^2=25^2
196+b^2=625
b^2=429
b=20.71 (approximate)
:)
a^2+b^2=c^2
14^2+b^2=25^2
196+b^2=625
b^2=429
b=20.71 (approximate)
:)
You might be interested in
Answer:
Step-by-step explanation:
Nathan's score is 11 less than 2 times Zac's score.
Let Z points be Zac's score and N points be Natan's score. then
2 times Zac's score = 2Z
11 less than 2 times Zac's score = 2Z -11
So, N = 2Z - 11
1. If Z=6, then
2. If Z=7, then
3. If Z=8, then
4. If Z=9, then
Thus, four other possibilities are
Question 1
There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are
ways of arranging the letters, which equal to 210 ways
Question 2
There are seven swimmers in total.
There are
ways of choosing the first winner, which is 7 ways
There are
ways of choosing the second winner, which is 6 ways
There are
ways of choosing the third winner, which is 5 ways
There are 7×6×5=210 ways of choosing first, second, and third winner
Question 3
The probability of eating an orange and a red candy is
×
, which equals to 
The probability of eating two green candies is
×
which equals to 
There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are
Question 2
There are seven swimmers in total.
There are
There are
There are
There are 7×6×5=210 ways of choosing first, second, and third winner
Question 3
The probability of eating an orange and a red candy is
The probability of eating two green candies is