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VashaNatasha [74]
3 years ago
8

Parentheses 3 squared - 2 cubed parentheses 66

5E%7B3%7D%20%29%20%5E%7B66%7D%20" id="TexFormula1" title="( {3}^{2} - {2}^{3} ) ^{66} " alt="( {3}^{2} - {2}^{3} ) ^{66} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Answer:

1

Step-by-step explanation:

evaluate the parenthesis before raising to power 66

3² = 9 and 2³ = 8, hence

(3² - 2³)= (9 - 8) = 1

(3^2-2^3)^{66} = 1^{66} = 1


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On a number line, A is at 5 and B is at 50. Point X is the midpoint. Point T is 2/3 of the way from X to B. Determine the coordi
Lemur [1.5K]

Number lines are used to represent points at regular interval.

The coordinate of point T on the number line is: 46.5

Given that:

A =5

B = 50

The coordinate of X at the midpoint is:

X = \frac{B + A}{2}

So, we have:

X = \frac{50+5}{2}

X = \frac{55}{2}

X = 27.5

Point T is at 2/3 from X to B.

The coordinate of T is calculated using:

T = X + \frac 23 (B - X + 1)

So, we have:

T = 27.5 + \frac 23 (55 - 27.5 + 1)

T = 27.5 + \frac 23 (28.5)

T = 27.5 + 19

T = 46.5

<em>Hence, T is located at 46.5</em>

Read more about number lines at:

brainly.com/question/18611090

6 0
2 years ago
An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic. Step 2 of 2 : S
ziro4ka [17]

Answer:

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Sample of 421 new car buyers, 75 preferred foreign cars. So n = 421, \pi = \frac{75}{421} = 0.178

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.151

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.205

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

8 0
2 years ago
Melissa sees a lighthouse from her sailboat. She knows the height of the lighthouse is 154 feet. She uses a measuring device and
Alex_Xolod [135]

Answer:

219.9  feet to the nearest tenth.

Step-by-step explanation:

Use trigonometry:

tan 35 = opposite / adjacent side

= 154/x

x =  154 / tan35

= 219.93

6 0
3 years ago
Read 2 more answers
Ann, Claire, and Josh collect stickers. One week, Ann collects 7 more stickers than Josh. Josh collects twice as many stickers a
UkoKoshka [18]

Answer:

Claire = 30 stickers

Josh = 60 stickers

Ann = 67 stickers

Step-by-step explanation:

Let

Claire stickers= x

Josh = 2x

Ann= 2x + 7

Total stickers = 157

Total stickers = Claire stickers + Josh stickers + Ann stickers

157 = x + (2x) + (2x+7)

157 = x + 2x + 2x + 7

157 = 5x + 7

Subtract 7 from both sides

157 - 7 = 5x + 7 - 7

150 = 5x

Divide both sides by 5

150/5 = x

30 = x

x = 30

Claire stickers= x

=30 stickers

Josh = 2x

= 2(30)

= 60 stickers

Ann= 2x + 7

= 2(30) + 7

= 60 + 7

= 67 stickers

Claire = 30 stickers

Josh = 60 stickers

Ann = 67 stickers

6 0
3 years ago
The following graph shows the distance Thomas is from his home (in meters) for a period of 2 minutes. Determine the average rate
irga5000 [103]
The answer:
<span>the average rate of change for the first 50 seconds:
it  is v= 100 m/ 50 s = 2 m/s
</span><span>Thomas speed is 2 m in each second for the first 50 seconds.

</span><span>The average rate of change for the 70 remaining seconds:
the time is between [70; 120]
so the distance is d= 200m - 40m= 160m
the average rate is
v= 160m / 70 s = 2 . 28m /s

</span>
6 0
3 years ago
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