Question

Pls Answer Quickly!NO LINKS OR IRRELAVENT PICTURES

Answer 1

Answer:

Option B

Step-by-step explanation:

Given that cosθ = $-\frac{3}{10}$

Since, θ is an angle in quadrant II therefore, cosine value is negative

Now we will find the tangent ratio from the given triangle.

tanθ = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

From the given triangle,

By applying Pythagoras theorem in the given right triangle,

AC² = AB² + BC²

AB² = 10² - 3²

       = 100 - 9

       = 91

AB = √91

tanθ = $\frac{AB}{BC}$

Now, tanθ = $\frac{\sqrt{91} }{3}$

Since, θ is in second quadrant therefore, tangent of the angle will be negative.

tanθ = $-\frac{\sqrt{91} }{3}$

Option B is the answer.