Hello!
Let's write some important information contained in the exercise:
• hotdogs: $2.59 (,x,)
,
• hamburgers: $5.29 (,y,)
He needs 11 packages. Let's write it:
• x + y = 11
He spent a total of $39.29. We can write it as:
• 2.59x + 5.29y = 39.29
Now, let's solve these two equations as a linear system:
First, let's isolate x in equation A:
Now, we will replace where's x by 11-y in equation B:
As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.
Step-by-step explanation:
can you please show the picture too
Answer:
Step-by-step explanation:
let 7 + 3√2 be an rational number where
7+3√2 = a/b [ a and b are coprime and b is not equal to zero]
3√2= a/b-7
3√2 =( a-7b) /b
√2 = (a-7b) /3b .....(i)
Now ,from equation (i) ,we get that √2 is rational but we know that √2 is irrational. so actually 7 + 3√2 is irrational not rational. thus our assumption is wrong. The number is irrational.
Make bottom numbers same
convert to improper fraction
1 and 5/6=1+5/6=6/6+5/6=11/6
1/2 and 11/6
2 times 3=6
1/2 times 3/3=3/6
1/2+11/6=3/6+11/6=(4+11)/6=14/6
answer is A
