The first number is 5 and the second number is 7
When
, you have
Now assume this is true for
, i.e.
and under this hypothesis show that it's also true for
. You have
In other words, there exists
such that
Rewriting, you have
and this is equivalent to
modulo 9, as desired.
Answer: z = 3
Step-by-step explanation: To solve this equation for <em>z</em>, we can first combine our like terms on the left side of the equation. Since 12 and 7 both have <em>z</em> after their coefficient, we can subtract 12z - 7z to get 5z.
Now we have 5z - 2 = 13.
To solve from here, we add 2 to the left side of the equation in order to isolate 5z. If we add 2 to the left side, we must also add 2 to the right side. On the left side, the -2 and +2 cancel out. On the right, 13 + 2 simplifies to 15.
Now we have 5z = 15.
Solving from here, we divide both sides of the equation by 5 to get <em>z</em> alone. On the left side, the 5's cancel out and we are simply left with <em>z</em>. On the right side, 15 divided by 5 simplifies to 3 so we have z = 3.
Answer:
I know #1 is a
Step-by-step explanation:
#1 is a because the bus stops twice reaching zero speed to pick up riders then he stops again but since he has to slow down it's not a instant stop so it gradually decelerates twice but since it has a speed it has a constant line (straight) another easy way to tell us to look at the speed and then look the the graph and see if they match so you can elimnate a answer
