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Elena-2011 [213]
3 years ago
12

0.025 0.25 0.205 0.052 order smallest to biggest

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0
0.025, 0.052, 0.205, 0.25 I believe.  It's been awhile since I've been in Middle School, though. :(
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Find the area, a rectangle with a length of 4 cm and a width of 2.5 cm
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Answer:

10

Step-by-step explanation:

4x2.5=10CM2

the area of a rectangular =width multiply its length

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What are the first 5 numbers of pie?​
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The answer is:

3.14159

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Perform the indicated computation. Write the answer in scientific notation. 12x10^4\3x10^−2
Paul [167]

Let us consider the given expression:

\frac{12 \times 10^{4}}{3 \times 10^{-2}} in the scientific notation.

= \frac{12 \times 10^{4} \times 10^{2}}{3 }

[Using the law of exponents, which states

a^{m} \times a^{n} = a^{m+n} ]

= \frac{12 \times 10^{6}}{3}

On dividing, we get

= 4 \times 10^{6}

Hence, it is the required scientific notation of the given expression.

6 0
3 years ago
I need help is it A B C or D
sweet-ann [11.9K]
All you have to do is plug it into slope-intercept form, which is y = mx + b

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4 0
3 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
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