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Elena-2011 [213]
3 years ago
12

0.025 0.25 0.205 0.052 order smallest to biggest

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0
0.025, 0.052, 0.205, 0.25 I believe.  It's been awhile since I've been in Middle School, though. :(
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Estimate the value of 52/ to the nearest whole number
REY [17]

It is 52 because when roundest to the whole number 52 is closest


6 0
3 years ago
9/34 × 17/6 =<br><br> PLEASE HELP
Deffense [45]

It would equal 0.75 and as a fraction it is 3/4

4 0
3 years ago
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Hence factorize completely the expression<br>9x³y² - 4xy⁴​
Aloiza [94]

Step-by-step explanation:

9 {x}^{3} {y}^{2}  - 4x {y}^{4}  \\  = x {y}^{2} (9 {x}^{2}  - 4 {y}^{2} )

4 0
3 years ago
Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions
monitta
I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take z=y', so that z'=y'' and we're left with the ODE linear in z:

y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2

Now suppose y has a power series expansion

y=\displaystyle\sum_{n\ge0}a_nx^n
\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}
\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}

Then the ODE can be written as

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0

\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0

All the coefficients of the series vanish, and setting x=0 in the power series forms for y and y' tell us that y(0)=a_0 and y'(0)=a_1, so we get the recurrence

\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}

We can solve explicitly for a_n quite easily:

a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}

and so on. Continuing in this way we end up with

a_n=\dfrac{a_1}{n!}

so that the solution to the ODE is

y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x

We also require the solution to satisfy y(0)=a_0, which we can do easily by adding and subtracting a constant as needed:

y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}
4 0
3 years ago
Solve for x in the diagram below.
max2010maxim [7]

1: Identify the angle.

<em>The following angle is a 90.</em>

2: Set up the equation.

<em>x + (3x + 10) = 90</em>

3: Combine like terms.

<em>4x + 10 = 90</em>

4: Solve for x.

<em>4x + 10 = 90</em>

<em>      -10 =   - 10</em>

<em>--------------------------</em>

<em>4x = 80</em>

<em>------------------</em>

<em>4          4</em>

<em>x = 20</em>

Your answer is x = 20.

Hope this helps! Have a good day/night! c:


6 0
3 years ago
Read 2 more answers
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