Answer:
C) 81.49
Step-by-step explanation:
Use the order of operations
PEMDAS
8² ÷ 4 + 3.7(42.3 - 24.6)
Parentheses
8² ÷ 4 + 3.7(17.7)
Exponent
64 ÷ 4 + 3.7(17.7)
Multiplication
64 ÷ 4 + 65.49
Division
16 + 65.49
Addition
81.49
Answer:
b
Step-by-step explanation:
Answer:
39.8 ml milk
Step-by-step explanation:
<u>DATA:</u>
<em>Total milk and butter cooper needs: 70.4 ml</em>
<em>Total butter needed: 30.6 ml</em>
<em>Total milk needed: m</em>
Milk + Butter = Total ml
m + 30.6 = 70.4
m = 70.4 - 30.6
m = 39.8 ml
Therefore, Cooper needs 39.8 ml milk for his recipe.
!!
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A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a load of 8.00 kg is hung on its end. Find the stress, the strain, and the Young’s modulus for the material of the wire.
Solution:
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a lo
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prev Statement of a problem № 2618 next
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a load of 8.00 kg is hung on its end. Find the stress, the strain, and the Young’s modulus for the material of the wire.
Solution:
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a lo
main
prev Statement of a problem № 2618 next
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a load of 8.00 kg is hung on its end. Find the stress, the strain, and the Young’s modulus for the material of the wire.
Solution:
A metal wire 75.0 cm long and 0.130 cm in diameter stretches 0.0350 cm when a lo
main
prev Statement of a problem № 2618 next