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Komok [63]
2 years ago
13

Find the missing length indicated

Mathematics
1 answer:
OleMash [197]2 years ago
4 0

Answer:

<em>x = 15</em>

Step-by-step explanation:

You might be interested in
One of the legs of a right triangle measures 12 cm and the other leg measures 9 cm.
PolarNik [594]

Answer:

15cm

Step-by-step explanation:

a^2+b^2=c^2

12^2+9^2=c^2

144+81=c^2

c^2=225

c=15

7 0
2 years ago
Read 2 more answers
A CLOSER LOOK AT Compound Inequalities We previously learned that compound inequalities are two inequalities joined by the word
alex41 [277]

Answer:

The sign at the ticket booth should read "Guests that are under 3 years old or over 62 years old get free admission!"

Step-by-step explanation:

Compound inequalities are the combination of two inequalities by the words "or" or "and".

In the given example, the compound inequality is,

Guests that are under 3 years old and over 62 years old get free admission!

The given inequality can be broken into two individual inequalities as,

Inequality 1: Guests that are under 3 years old get free admission

Inequality 2: Guests that are over 62 years old get free admission

The above two inequalities are combined by "and" in the given compound inequality.

Now, "and" signifies that both the conditions or inequalities should be fulfilled at the same time. But a guest can either be under 3 years old or he/she should be older than 62. Both the conditions cannot be fulfilled at the same time and hence, the sign doesn't make any sense.

To correct the sign, "and" should be replaced with "or".

Therefore, the corrected sign at the ticked booth should read "Guests that are under 3 years old or over 62 years old get free admission!".

For more details, refer to the link:

brainly.com/question/20296065?referrer=searchResults

3 0
2 years ago
The answer to this problem
Alexandra [31]
I have more problems then this.
6 0
2 years ago
I need help if you get it right I will mark you as brainlest
musickatia [10]

Answer:

D. 9/DF=18/16.......the answer

3 0
3 years ago
AYUDAAA porfavorrrr primera urna 6 bolas verdes y 3 rojas segunda urna 3 verdes, 3 blancas y 3 rojas tercera urna 6 verdes, 1 bl
marin [14]

We have the following information:

first urn: 6 green balls and 3 red ones

total: 6 + 3 = 9

second urn: 3 green, 3 white and 3 red

total: 3 + 3 + 3 = 9

third urn: 6 green, 1 white and 2 red

total: 6 + 1 + 2 = 9

a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.

b) probability of drawing a green, red and white ball.

first urn:

green = 6/9 = 66.66%

red = 3/9 = 33.33%

white = 0/9 = 0%

second urn:

green = 3/9 = 33.33%

red = 3/9 = 33.33%

white = 3/9 = 33.33%

third urn:

green = 6/9 = 66.66%

red = 2/9 = 22.22%

white = 1/9 = 11.11%

c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%

d) without a green ball, the third ballot box would look like this:

5 green balls, 2 red balls and 1 white ball, with a total of 8.

The probability of drawing would be:

green = 5/8 = 62.5%

red = 2/8 = 25%

white = 1/8 = 12.5%

7 0
2 years ago
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