All categories

3 years ago

Please help if you know how to do the base angle theorem I could really use some help

Mathematics

1 answer:

jenyasd209 [6]3 years ago

7 0

Answer:

x = 22°, y = 70°

Step-by-step explanation:

Isosceles Triangles

The base angles of an isosceles triangle are those formed by the base and one leg of the triangle.

On the other side, the base angles theorem converse states if two angles in a triangle are congruent, then the sides opposite those angles are also congruent.

We are given an isosceles triangle with base angles 3x-11 and 2x+11. Applying the theorem as explained above:

3x - 11 = 2x + 11

Subtracting 2x:

x - 11 = 11

Adding 11:

x = 22

The base angles have a measure of

3x - 11 = 3*22 - 11 = 55°

Thus, the remaining angle of the triangle is:

y = 180° - 2*55° = 180° - 110° = 70°

x = 22°, y = 70°

You might be interested in

A 150-foot fence encloses a garden. What is the length of each side of the garden

Helga [31]

I Think 150 divided by 4=37.5

4 0

3 years ago

Read 2 more answers

5(4 - 1) The Second person to answer gets Brainliest

AnnyKZ [126]

Answer:

the answer is 15 because you have to do the problem in the parentheses first then multiply by 5

8 0

2 years ago

college students are offered a 8% discount on a textbook that sells for $31.50 if the sales tax is 8% , find the cost of the tex

zhenek [66]

The answer should be $33.99

8 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

3 0

3 years ago

Help please, look at picture for question

alexgriva [62]

Answer:

whats the title of the page ill find the answers to thw whole sheet n and while your at it do you know Why was Kor surprised that Groening embraced her???

Step-by-step explanation:

8 0

3 years ago