Answer:
<h2>A. <em><u>2</u></em><em><u>1</u></em><em><u>4</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em></h2>
Step-by-step explanation:
<h3>#CarryOnLearning</h3>
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
<span>In statistics finding percentiles relates to the standard deviation and something called a z-score. For normally distributed data the z-score represents how many standard deviations above or below the mean that group is a part of. The z-score for normally distributed data for the 90th percentile is 1.28. The standard deviation is then multiplied by the z-score to find, in this case, the shotlrtest height needed to be in the 90th percentile of this population. In this case to be in the 90th percentile your height must be 60.27 inches.</span>
Answer:
145°
Step-by-step explanation:
There are a couple of ways you can get there:
1. ∠ACB is a right angle, 90°. Hence, ∠BAC is the complement of ∠ABC, so is ...
... ∠BAC = 90° -∠ABC = 90° -55° = 35°
Then, ∠BAC and ∠BAD are a linear pair, so total 180°. That makes ∠BAD the supplement of ∠BAC, so ...
... ∠BAD = 180° -35° = 145°
2. ∠BAD is the exterior angle at A for the triangle ABC. It will have a measure that is the sum of the opposite interior angles: given ∠ABC = 55° and right angle ACB = 90°.
... ∠BAD = 55° +90° = 145°
Answer:
-12
Step-by-step explanation:
(-2)(-3)^2-2(2-5). Original
-2(9)-2(2-5) Distribute Exponents
-18-4+10 Distribute Parentheses
-22+10 Do subtraction
-12 Do Addition
